How can I create a sine graph that has a period of 2π and an amplitude of 3?
1 answer:
Hello!
The parent function of the graph of sin is y = sin(x).
Amplitude is the maximum displacement on the graph of a function.
Period is the displacement of x at which the graph of a function begins to repeat.
The period can be found by using the formula: .
Since the amplitude is 3, the graph of sin is y = 3sin(x).
Given the period 2π, we can substitute this value into the given formula, , to find B.
2π = 2π / B (multiply B to both sides)
2π · B = 2π (divide by 2π)
B = 1
Thus, the equation is y = 3sin(x). I'll post the graph as well.
You might be interested in
Answer:
Step-by-step explanation:
Given:
Need:
First, let's look at the identities:
sum:
difference:
The question asks to find sin(A - B); therefore, we need to use the difference identity.
Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.
sin(A) =
cos(A) =
sin(B) =
cos(B) =
Plug these values into the difference identity formula.
Multiply.
Add.
This is your answer.
Hope this helps!