How can I create a sine graph that has a period of 2π and an amplitude of 3?
1 answer:
Hello!
The parent function of the graph of sin is y = sin(x).
Amplitude is the maximum displacement on the graph of a function.
Period is the displacement of x at which the graph of a function begins to repeat.
The period can be found by using the formula: .
Since the amplitude is 3, the graph of sin is y = 3sin(x).
Given the period 2π, we can substitute this value into the given formula, , to find B.
2π = 2π / B (multiply B to both sides)
2π · B = 2π (divide by 2π)
B = 1
Thus, the equation is y = 3sin(x). I'll post the graph as well.
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Answer:
y = 3x + 23 and
Step-by-step explanation:
The first equation is 9x - 3y = - 69 and we have to write it in slope-intercept form.
Now, 9x - 3y = - 69
⇒ 3x - y = - 23 {Dividing both sides by 3}
⇒ 3x + 23 = y
⇒ y = 3x + 23 {Interchanging the sides} (Answer)
The second equation is x - 3y = - 6 and we have to write it in slope-intercept form.
Now, x - 3y = - 6
⇒ x + 6 = 3y
⇒ 3y = x + 6 {Interchanging the sides}
⇒ {Dividing both sides by 3}
⇒ (Answer)