Question

A restaurant menu has five kinds of soups, seven kinds of main courses, six kinds of desserts, and five kinds of drinks. If a customer randomly selects one item from each of these four categories, how many different outcomes are possible

Answer 1

Answer:

1050

Explanation:

Multiply each of the choices together.

5 x 7 x 6 x 5 = 1050

Answer 2

Answer: 1050

Step-by-step explanation:

Number of combinations of selecting r things out of n = $^nC_r=\dfrac{n!}{r!(n-r)!}$

such that $^nC_1=n$

Given: A restaurant menu has 5 kinds of soups, 7kinds of main courses, 6 kinds of desserts, and 5 kinds of drinks.

If a customer randomly selects one item from each of these four categories, then by fundamental counting principle , the number of different outcomes are possible = $^5C_1\times \ ^7C_1\times\ ^6C_1\times\ ^5C_1 =5\times7\times6\times5=1050$

hence, total number of outcomes = 1050