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enyata [817]
3 years ago
12

-3 1/4 x+25 =2 1/4x-13 1/2

Mathematics
1 answer:
ELEN [110]3 years ago
3 0

Answer:

x = 5348/45

Step-by-step explanation:

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If f(x) = x-9, then f '(x) =​
erica [24]

Answer:

1

Step-by-step explanation:

If you are just looking for the derivative, then all you need to use the power rule for this. Technically the x in (x-9) has a power to the 1, so really x^1-9. To use power rule, you bring down the exponent, in this case, 1, and then minus 1 from what the exponent was.

1x^(1-1) = 1x^0. The derivative of any constant is 0, so don't even worry about the -9. We know that anything raised to the zero is just 1, so in this case your answer is 1.

Hope this helps :)

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2 years ago
What cross section shape is formed when the figure is cut as shown?
kirza4 [7]

Answer:

Triangle

Step-by-step explanation:

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2 years ago
A customer is late paying their renewal registration fee. The renewal registration fee is $142.16 and the late fee is 63% of the
Andre45 [30]
$124.56 because if you have 63% you change it to a decimal so it is not .63 and you multiply it by 146.16 and then add the 35 you get 124.56
8 0
3 years ago
What is 2 + 2? <br> pls help when you can! &lt;3
Anna [14]

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5 0
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Read 2 more answers
Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
2 years ago
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