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Lorico [155]
3 years ago
8

To get there students and chaperones will travel in buses,vans,and cars Buses have 40 seats and cost $300 to rent. Vand have 16

seats and cost $125 to rent. Cars have 5 seats and cost $40 to rent. Which is the most efficient way to transport dancers to and from the competition? How much will renting the vehicles cost?
Mathematics
1 answer:
elixir [45]3 years ago
6 0
How many students would there be? did not see that information if that is the question but if not I say go with the bus that has more seats yes it is more expensive but more space is better!
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If 6x^4+8x^3-5x^2+ax+b is completely divisible by 2x^2-5 then find the value of a and b.
mixas84 [53]

Answer:

  • The value of a = -20
  • The value of b=-25

Step-by-step explanation:

Let

p(x)=6x^4+8x^3-5x^2+ax+b

and

q(x)=2x^2-5

As q(x) is exactly divisible, so, the remainder is 0.

∴ p(x)=q(x).g(x)+r(x)

6x^4 + 8x^3 - 5x^2 + ax + b = (\sqrt{2} x - \sqrt{5})(\sqrt{2} x + \sqrt{5}) g(x)

As the R.H.S becomes 0 when x = \sqrt{\frac{5}{2} } and x = -\sqrt{\frac{5}{2} }.

And

by substituting x = \sqrt{\frac{5}{2} }

6(\sqrt{\frac{5}{2} } )^4 + 8(\sqrt{\frac{5}{2} } )^3 - 5(\sqrt{\frac{5}{2} } )^2 + a(\sqrt{\frac{5}{2} } ) + b = 0

25 + 20( \frac{\sqrt{5}}{\sqrt{2}} ) + a( \frac{\sqrt{5}}{\sqrt{2}}) +b =0...[A]

by substituting x = -\sqrt{\frac{5}{2} }

25 - 20( \frac{\sqrt{5}}{\sqrt{2}} ) - a( \frac{\sqrt{5}}{\sqrt{2}}) +b =0.....[B]

Adding Equation [A] and equation [B]

50 +2b =0

b=-25

Subtracting Equation [A] and equation [B]

40(\sqrt{\frac{5}{2} } ) + 2a(\sqrt{\frac{5}{2} } ) =0

a = -20

Therefore,

  • The value of a = -20
  • The value of b=-25

<em>Keywords:</em><em> equation, solution</em>

<em> Learn more about equation solution from brainly.com/question/12687078</em>

<em> #learnwithBrainly</em>

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