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Oksi-84 [34.3K]
3 years ago
10

Is the function f(x) =(4)^x -2 an exponential function. If so, identify the base. If not, why not?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
7 0

Answer:

Yes.

Base: 4

Step-by-step explanation:

Since we have 4 to the power of x, we do indeed have an exponent. The -2 just signifies vertical movement down.

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8 0
3 years ago
A Wheel has a radius of 15 cm. Approximately how how far does it travel in 4 revolutions
victus00 [196]

Answer:

Roughly 376.99 cm(If im doing this right.

Step-by-step explanation:

6 0
2 years ago
Help pleaseeeeeeeeee
sergij07 [2.7K]

9514 1404 393

Answer:

  47 -6√10

Step-by-step explanation:

As you know, the area of a square is the square of the side length. It can be helpful here to make use of the form for the square of a binomial.

  (a -b)² = a² - 2ab + b²

  (√2 -3√5)² = (√2)² - 2(√2)(3√5) + (3√5)²

  = 2 - 6√10 + 3²(5)

  = 47 -6√10

__

<em>Check</em>

  √2-3√5 ≈ -5.29399 . . . . . . . . note that a negative value for side length makes no sense, so this isn't about geometry, it's about binomials and radicals

  (√2-3√5)² ≈ 28.02633

  47 -6√10 ≈ 28.02633

5 0
3 years ago
If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
6 0
3 years ago
HELP! Simplify: -6 (5/3x+4)<br> A) -10x-24. B) -10x-24. C) -10x+4. D) -10x-4.
pashok25 [27]

Answer:

D) -10x-4

Step-by-step explanation:

−6(5/3x+4)

=(−6)(5/3x+4)

=(−6)(5/3x)+(−6)(4)

=−10x−24

6 0
3 years ago
Read 2 more answers
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