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kari74 [83]
3 years ago
11

PLEASE HELP !!

Mathematics
1 answer:
drek231 [11]3 years ago
6 0
Umm is this the problem we need to solve?
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A bike repair shop charges $15.40 for parts plus $8.50 for labor to fix Jessica's bike. a) How much would Jessica pay for 2.5 ho
Alika [10]
15.40 + 8.50l (l is variable for labor)
8.50 x 2.5 = 21.25
15.40 + 21.25 = 36.65.
That is the answer for A.

504.20 - 15.40 = 488.80
488.80 / 8.50 = <span>57.50
About 57.50 hours for B.</span>
7 0
3 years ago
PLEASE HELP!!!
goldfiish [28.3K]
The correct answer to the first question is: A'(-5, 6)



The second answer is un-answerable, because the pictures you have provided do not display triangles.
6 0
3 years ago
Read 2 more answers
13. f(x) = -x + 4x^3 -2
Oksi-84 [34.3K]

Answer:

x = 5

Step-by-step explanation:

7 0
3 years ago
The measure of angle P is five less than four times the measure of angle Q. Of angle P and angle Q are supplementary angles, fin
Andru [333]

Answer:

m∠P=140°

Step-by-step explanation:

Given:

∠P and ∠Q are supplementary angles.

The measure of angle P is five less than four times the measure of angle Q.

To find m∠P

Solution:

The measure of angle P can be given as:

A) m\angle P=4(m\angle Q-5)

And

B) m\angle P+ m\angle Q=180 [Definition of supplementary angles]

Substituting equation A into B.

4(m\angle Q-5)+ m\angle Q=180

Solving for m\angle Q

Using distribution:

4m\angle Q-20+ m\angle Q=180

Simplifying by combining like terms.

5m\angle Q-20=180

Adding 20 to both sides.

5m\angle Q-20+20=180+20

5m\angle Q=200

Dividing both sides by 5.

\frac{5m\angle Q}{5}=\frac{200}{5}

m\angle Q=40

Substituting m\angle Q=40 in equation B.

m\angle P+ 40=180

Subtracting both sides by 40.

m\angle P+ 40-40=180-40

m\angle P=140

Thus, we have:

m∠P=140° (Answer)

7 0
3 years ago
A drug used to relieve anxiety and nervousness has a half-life of 16 hours. if a doctor prescribes one 2.8-milligram every 24 ho
dlinn [17]

After 24 hours, 35.4% of the initial dosage remains on the body.

<h3>What percentage of the last dosage remains?</h3>

The exponential decay is written as:

f(x) = A*e^{-k*x}

Where A is the initial value, in this case 2.8mg.

k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:

k = ln(2)/16h

Replacing all that in the above formula, and evaluating in x = 24 hours we get:

f(24h) = 2.8mg*e^{-24h*ln(2)/16h} = 0.9899 mg

The percentage of the initial dosage that remains is:

P = \frac{0.9899mg}{2.8mg}*100\% = 35.4\%

If you want to learn more about exponential decays:

brainly.com/question/11464095

#SPJ1

8 0
2 years ago
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