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Luda [366]
3 years ago
15

What is the Median in the following Number sequence: 19, 13, 16, 15, 8, 14,6

Mathematics
1 answer:
ANEK [815]3 years ago
5 0

Answer:

13.5

Step-by-step explanation:

1st: organize the numbers into counting order.

6, 8, 13, 14, 15, 19

2nd: find the number in the middle of the sequence. for this specific question its two numbers. 13 and 14. if it is two number then you just use the number in between them. in this case it's 13.5

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Using the following equation, find the center and radius of the circle: x^2 + y^2 +2x − 4y − 20 = 0
DanielleElmas [232]
You have to complete the squares on both the x terms and the y terms in order to solve this. Move the 20 over to the other side so it's negative. Group the x terms together and complete the square to get (x^2+2x+1) and then do the same with the y terms: (y^2-4y+4). You have to add 1 and 4 to other side with the 20 to get a 25. Then create 2 perfect square binomials within each x and y value to get the vertex coordinates: (x+1)^2 + (y-2)^2 = 25. This tells us that the vertex is located at (-1, 2) and the radius is the square root of 25 which is 5.So the answer is the first choice above.
6 0
3 years ago
What is the value of 6n-2
ad-work [718]
<span>Factor <span><span>6n</span>−2
</span></span><span><span>6n</span>−2
</span><span>=<span>2<span>(<span><span>3n</span>−1</span>)
</span></span></span><u>Answer: </u><span>2<span>(<span><span>3n</span>−1</span><span>)</span></span></span>
5 0
3 years ago
What type of muffin coast the least?
andre [41]
A). 12 ÷ $7.20 = about $1.67 per muffin
b). 8 ÷ $4.40 = about $1.81 per muffin
c). 6 ÷ $4.50 = about $1.33 per muffin

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7 0
3 years ago
Ex 7) Imagine a mile-long bar of metal such as the rail along railroad tracks. Suppose that the rail is anchored on both ends an
Fantom [35]

9514 1404 393

Answer:

  about 44.5 feet

Step-by-step explanation:

We can write relations for the height of the rail as a function of initial length and expanded length, but the solution cannot be found algebraically. A graphical solution or iterative solution is possible.

Referring to the figure in the second attachment, we can write a relation between the angle value α and the height of the circular arc as ...

  h = c·tan(α) . . . . . . where c = half the initial rail length

Then the length of the expanded rail is ...

  s = r(2α) = (c/sin(2α)(2α) . . . . . . where s = half the expanded rail length

Rearranging this last equation, we have ...

  sin(2α)/(2α) = c/s

It is this equation that must be solved iteratively. We find the solution to be ...

  α ≈ 0.0168538794049 radians

So, the height of the circular arc is ...

  h = 2640.5·tan(0.0168538794049) ≈ 44.4984550191 . . . feet

The rail will bow upward by about 44.5 feet.

_____

<em>Additional comments</em>

Note that s and c in the diagram are half the lengths of the arc and the chord, respectively. The ratio of half-lengths is the same as the ratio of full lengths: c/s = 2640/2640.5 = 5280/5281.

We don't know the precise shape the arc will take, but we suspect is is not a circular arc. It seems likely to be a catenary, or something similar.

__

We used Newton's method iteration to refine the estimate of the angle from that shown on the graph. The iterator used is x' = x -f(x)/f'(x), where x' is the next guess based on the previous guess of x. Only a few iterations are required obtain an angle value to full calculator precision.

3 0
3 years ago
LOOK AT THE PICTURE PLZ NEED HELP
Sunny_sXe [5.5K]

Answer:

J. 1.26

Step-by-step explanation:

Because it's getting multiplied by 1.26 every year.

7 0
3 years ago
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