Question

Please help me with this! Show work if possible

Answer 1

Answer:

True

Step-by-step explanation:

Suppose you have a quadratic function

$ax ^ 2 + bx + c = 0$

Factoring this expression results in:

$ax ^ 2 + bx + c = (x-h) (x-k) = 0$

Where h and k are real numbers.

Then the function is equal to 0 when $x = h$ and when $k = 0$.

Therefore h and k will always be the solutions when we have the quadratic function factored in the form

$(x-h)(x-k) = 0$

Since we have ensured that the factors of the function contain only real numbers, then h and k are real numbers, and x and y must also be real numbers. Therefore solutions to an equation in this form will always be real solutions.

The statement is true