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Nadusha1986 [10]
3 years ago
10

What is the result of (5/8)⁴

Mathematics
2 answers:
Fiesta28 [93]3 years ago
7 0

Answer:

625/4096

Step-by-step explanation:

Sloan [31]3 years ago
5 0

Answer: 5/8 ÷ 4 = 5/32 in fraction form. 5/8 ÷ 4 = 0.1563 in decimal form.

Step-by-step explanation:

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Clara writes the following proof for the theorem: If the diagonals of a quadrilateral bisect each other, the quadrilateral is a
zheka24 [161]

Answer:

  CPCTC

Step-by-step explanation:

Statements 3 and 4 show the top and bottom triangles are congruent, and the left and right triangles are congruent. Statement 5 is making use of these facts to claim that the alternate interior angles are congruent. This claim is valid because ...

  Corresponding Parts of Congruent Triangles are Congruent (CPCTC)

7 0
3 years ago
Check whether <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B5%7D%20" id="TexFormula1" title=" \frac{4}{5} " alt=" \f
steposvetlana [31]

Answer:

Non terminating

Step-by-step explanation:

4/5=0.8 so non terminating

Hope this helps :D

6 0
2 years ago
Hello!!!! :) please help with this math problem! thank u so much!!!! i really appreciate it &lt;3
Morgarella [4.7K]

Answer:

AGREE!

Step-by-step explanation:

"I agree with Lin, she used the correct formula to get this answer"

3 0
2 years ago
Please help! Find the perimeter.
Aleksandr [31]
The answer is 4x+28 it was pretty simple you just had to add up all the sides
3 0
3 years ago
Let $a$ and $b$ be nonzero real numbers such that
algol [13]
<h3>Answer:   -7/2</h3>

=========================================================

Explanation:

Let's expand out (2 - 7i)(a + bi) using the FOIL rule

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7bi^2

(2 - 7i)(a + bi) = 2a + 2bi - 7ai - 7b(-1)

(2 - 7i)(a + bi) = 2a + 2bi - 7ai + 7b

(2 - 7i)(a + bi) = (2a+7b) + (2bi-7ai)

(2 - 7i)(a + bi) = (2a+7b) + (2b-7a)i

We're told the result is purely imaginary. What this means is that the real part (2a+7b) is zero, while the imaginary part (2b-7a) is nonzero. If both are zero, then we have 0+0i = 0 which is purely real.

For example, the complex numbers 0-7i and 0+2i are purely imaginary.

Let's use the fact that 2a+7b must be zero to do the following steps:

2a+7b = 0

2a = -7b

a = -7b/2

a/b = -7/2 which is the final answer

We must check to see if 2b-7a is nonzero

2b - 7a = 2b - 7(-7b/2)

2b - 7a = 2b + 24.5b

2b - 7a = 26.5b

The result is nonzero if and only if b is nonzero. Luckily we're told b is nonzero at the top of the problem. So we don't have any worries that (2b-7a) is zero.

Therefore, (2a+7b) + (2b-7a)i will be purely imaginary with a/b = -7/2

------------------

A concrete example:

Let a = -14 and b = 4

a/b = -14/4 = -7/2

(2-7i)(a+bi) = (2-7i)(-14+4i) = 0 + 106i which is purely imaginary.

I'll let you do the steps in expanding that out using the FOIL rule.

4 0
1 year ago
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