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3 years ago

13

At Furnace Woods School, enrollment increased from 320 students in 2006 to 349 students in 2007. What is the percent increase in

enrollment?

1 answer:

matrenka [14]3 years ago

7 0

Answer:

I'm not sure if this is correct, but I would say it increased by maybe 29 percent so sorry if i'm wrong

Step-by-step explanation:

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For the senior pic mr. Williams is using two cylinders to help keep the food cool the inside still there with the radius of 8 in

Rasek [7]

The answer is 1,695.6 in³.

The volume of the empty space is the difference of the bigger cylinder and the smaller cylinder: V = V1 - V2

The volume of the bigger cylinder is:
V1 = π r² h
r = 10 in
h = 15 in
π = 3.14

V1 = 3.14 * 10² * 15 = 4,710 in³

The volume of the smaller cylinder is:
V2 = π r² h
r = 8 in
h = 15 in
π = 3.14

V2 = 3.14 * 8² * 15 = 3,014.4 in³

The volume of the empty space is:
V = V1 - V2 = 4,710 in³ - 3,014.4 in³ = 1,695.6 in³

4 0

3 years ago

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 l

slamgirl [31]

Answer:

She will leave an extra video game which weighs 0.25lb

Step-by-step explanation:

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed?

Solution:

Weight of the items

hairdryer = 1.25 lb

hand-held video game = 0.6 lb

an extra video game = 0.25 lb music player = 0.4 lb

The total weight of the items

= 1.25lb + 0.25lb + 0.6lb + 0.4lb

= 2.5 lb.

Total weight - required weight

= 2.5lb - 2.25lb

= 0.25lb

2.5lb is 0.25lb greater than 2.25lb

Therefore, not all items can be added.

She has to leave out an item equivalent to 0.25lb

Item equivalent to 0.25lb is the extra video game

If Li leaves out the extra game, which weighs 0.25 lb, she’d have the maximum weight allowed.

5 0

3 years ago

A man hits a baseball when it is 4 ft above the ground with an initial velocity of 120 ft/sec. The ball leaves the bat at a 30 d

Sauron [17]

<span>et us assume that the origin is the floor right below the 30 ft. fence

To work this one out, we'll start with acceleration and integrate our way up to position.

At the time that the player hits the ball, the only force in action is gravity where: a = g (vector)
ax = 0
ay = -g (let's assume that g = 32.8 ft/s^2. If you use a different value for gravity, change the numbers.

To get the velocity of the ball, we integrate the acceleration
vx = v0x = v0cos30 = 103.92
vy = -gt + v0y = -32.8t + v0sin40 = -32.8t + 60

To get the positioning, we integrate the speed.
x = v0cos30t + x0 = 103.92t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + 60t + 4

If the ball clears the fence, it means x = 0, y > 30

x = 0 -> 103.92 t - 350 = 0 -> t = 3.36 seconds

for t = 3.36s,
y = -16.4(3.36)^2 + 60*(3.36) + 4
= 20.45 ft

which is less than 30ft, so it means that the ball will NOT clear the fence.

Just for fun, let's check what the speed should have been :)

x = v0cos30t + x0 = v0cos30t - 350
y = 1/2*(-32.8)t² + v0sin30t + y0 = -16.4t² + v0sin30t + 4

x = 0 -> v0t = 350/cos30
y = 30 ->
-16.4t^2 + v0t(sin30) + 4 = 30
-16.4t^2 + 350sin30/cos30 = 26
t^2 = (26 - 350tan30)/-16.4
t = 3.2s

v0t = 350/cos30 -> v0 = 350/tcos30 = 123.34 ft/s

So he needed to hit the ball at at least 123.34 ft/s to clear the fence.

You're welcome, Thanks please :)
</span>

6 0

3 years ago

Solve the following inequality.

Anika [276]

Solving the inequality given algebraically, the solution of the inequality for the value of m is:

<u>m < -4 OR m > 3</u>

<em><u>Given the following </u></em><em><u>inequality</u></em><em><u>,</u></em>

<em><u /></em> $\frac{m - 2}{3} < -2 \\$

or

4m + 3 > 15

Let's solve algebraically for the value of m in both inequality statements given.

$\frac{m - 2}{3} < -2 \\$

Multiply both sides by 3

$\frac{m - 2}{3} \times 3 < -2 \times 3\\\\m - 2 < -6$

Add 2 to both sides

$m - 2 + 2 < -6 + 2\\\\m < -4$

Or

4m + 3 > 15

Subtract 3 from each side

4m + 3 - 3 > 15 - 3

4m > 12

Divide both sides by 4

$\frac{4m}{4} > \frac{12}{4} \\\\$

m > 3

Therefore, solving the inequality given algebraically, the solution of the inequality for the value of m is:

<u>m < -4 OR m > 3</u>

<u></u>

<u></u>

Learn more here:

brainly.com/question/24434501

8 0

2 years ago

Olga’s family traveled 942 kilometers on the first day of their trip and 894.5 kilometers on the second day. How many more meter

lawyer [7]

47,500 hope i helped have a snazzy day

8 0

3 years ago

Read 2 more answers