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vichka [17]
3 years ago
9

Lena has 2 boxes of buttons A and B.In total are 1.200 buttons .She move 360 buttons from box A to B.There are now 3 times as ma

ny buttons in box B than box A.Homany buttons were in box A at the start?
Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:

660

Step-by-step explanation:

Let  A = number of buttons in Box A

and B = number of buttons in Box B

We have two conditions:

(1)            A + B = 1200

(2)       B + 360 = 3(A – 360)     Remove parentheses

          B + 360 = 3A - 1080      Subtract 360 from each side

(3)                 B = 3A - 1440       Substitute (3) into (1)

A + 3A - 1440 = 1200               Combine like terms

      4A - 1440 = 1200               Add 1440 to each side

                4A  = 2640               Divide each side by 4

                   A = 660

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Step-by-step explanation:

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40% of what number is 26
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Big Mack buys meat for the family reunion cookout. He needs to buy 11 packagesof meat. A package of hotdogs costs $2.59, and a p
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Hello!

Let's write some important information contained in the exercise:

• hotdogs: $2.59 (,x,)

,

• hamburgers: $5.29 (,y,)

He needs 11 packages. Let's write it:

• x + y = 11

He spent a total of $39.29. We can write it as:

• 2.59x + 5.29y = 39.29

Now, let's solve these two equations as a linear system:

\begin{cases}x+y=11\text{ equation A} \\ 2.59x+5.29y=39.29\text{ equation B}\end{cases}

First, let's isolate x in equation A:

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Now, we will replace where's x by 11-y in equation B:

\begin{gathered} 2.59x+5.29y=39.29 \\ 2.59(11-y)+5.29y=39.29 \\ 28.49-2.59y+5.29y=39.29 \\ -2.59y+5.29y=39.29-28.49 \\ 2.7y=10.8 \\ y=\frac{10.8}{2.7} \\  \\ y=4 \end{gathered}

As I called the hamburgers as 'y', we know that he bought 4 packages of hamburgers.

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