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4 years ago

12

Simon wants to drive 450 miles in 12 hours. He knows that stopping for breaks will take a total of 3 hours. What

1 answer:

V125BC [204]4 years ago

3 0

Answer:

I believe it would be 50

Step-by-step explanation:

If those 3 hours are included in those 12 to get there, then you'd want to subtract that to get your actual time spent driving. That would leave you with 9. Then, you'd divide that by 450 to get your answer. (This is if those 3 hours are included in that 12 hour time frame.)

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Can someone help me with this is for my test..?!!

andreev551 [17]

Answer:

4, 7, 6

Step-by-step explanation:

So we know that y=x/2

This can be though of y =1/2x

SO we can plug in the numbers into this equation to solbe for y:

y=1/2*8

=

y=4

SO that is our first fill in box answer.

Next we have 14:

y=1/2*14

=

y=7

So that is our second fill in box answer

Finally we have 3 for y. This is a bit strange, but all we do is plug in 3 for y and solve for x:

3=1/2*x

6=x

So that is the answer for the last fill in box answer.

Hope this helps!

7 0

3 years ago

Read 2 more answers

jekas [21]

I think the answer is A I’m not sure tho

6 0

3 years ago

Rectangle PQRS is dilated by a scale factor of 2 (k=2) with the origin as the center. What are the coordinates of R('?

Radda [10]

Answer:

Correct Answer: (8,2)

Step-by-step explanation:

<u>Dilation about the origin</u>

Most dilations in the coordinate plane use the origin, (0,0), as the center of the dilation.

In such cases, every point (x,y) dilated by a factor of k is mapped to the point (kx,ky).

The point R=(4,1) is dilated by a scale factor of 2 (k=2), thus the coordinates of its image are (2*4,2*1) = (8,2)

4 0

3 years ago

PLEASE HELP ME ASAP!!!

weqwewe [10]

Answer:

D

Step-by-step explanation:

a number expressed in standard form is

a × $10^{n}$ : 1 ≤ a < 10 and n is an integer

given

(7.5 × $10^{7}$ )(2 × 10³)

= 7.5 × 2 × $10^{(7+3)}$

= 15 × $10^{10}$

= 1.5 × $10^{1}$ × $10^{10}$

= 1.5 × $10^{(1+10)}$

= 1.5 × $10^{11}$

4 0

2 years ago

manu took a loan of Rs 5000 for one year at 12%per annum compounded quarterly .How much he has to pay after one year.

Shkiper50 [21]

Answer:

Amount pay after one year for compounded quarterly = Rs 5627.54

Step-by-step explanation:

Given as,

Manu took loan of Rs 5000 , So, Principal = Rs 5000

The rate of interest applied = 12% per annum compounded quarterly

The loan took for period of year = one

Now from the compounded method :

For compounded quarterly

Amount = principal $(1 + \frac{Rate}{4\times 100})^{4\times Time}$

Or, Amount = Rs 5000 $(1+ \frac{12}{4\times 100})^{4}$

Or, Amount = 5000 $(\frac{103}{100})^{4}$

Or, Amount = 5000 × 1.1255

∴ Amount = Rs 5627.54

Hence , The amount which Manu pay after one year at 12% per annum compounded quarterly is Rs 5627.54 Answer

5 0

3 years ago