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2 years ago

10. A circle has an arc with measure 80° and length 887. What is the diameter of the circle?

1 answer:

3 0

The diameter of the whole circle is 2*pi*radius . The arc length is then 80/360*pi*radius*=88*pi
radius=88*180/80
=44*180/40
=22*180/20
=11*180/10
=11*18
=(10+1)*18
=198
The diameter is 2*198=(200-2)=400-4=396

SO BASICALLY THE ANSWER IS 396

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Answer:

$\boxed{\sf sin\ C =\frac{40}{41}}$

Step-by-step explanation:

We need to find out the value of sinC using the given triangle . Here we can see that the sides of the triangle are 40 , 41 and 9 .

We know that the ratio of sine is perpendicular to hypontenuse .

$\sf\longrightarrow sin\theta =\dfrac{ perpendicular}{hypontenuse}$

Here we can see that the side opposite to angle C is 40 , therefore the perpendicular of the triangle is 40. And the side opposite to 90° angle is 41 . So it's the hypontenuse . On using the ratio of sine ,

$\sf\longrightarrow sinC =\dfrac{ p}{h}\\\\\sf\longrightarrow sin\ C =\dfrac{AB}{AC}$

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