Answer is d=2 1/3
Because find area of a triangle =1/2×b×h
U will get 7/3
Answer:
The area of the rectangle is 15y^6 -40y^5 + 10y^4
Step-by-step explanation:
In this question, given the width and length of a rectangle in polynomial form, we are asked to express the area of the rectangle in terms of the polynomials.
Generally, the area of a rectangle A is mathematically equal to Length * width
Using the terms in the question, our area A = 5y^3 [3y^3 -8y^2 +2y]
Opening this bracket we have;
15y^6 -40y^5 + 10y^4
Answer:
Step-by-step explanation:
ASTC (I use a sentence to memorize: All Students Take Calculus):
Q1 - All functions are positive
Q2 - Sine is positive (Cosecant is positive as well) (all others negative)
Q3 - Tangent is positive (Cotangent is positive as well) (all others negative)
Q4 - Cosine is positive (Secant is positive as well) (all others negative)
Applying ASTC:
Secant is negative, so it can't be in quadrant 1, and quadrant 4.
Quadrant 2 - Sine and Quadrant 3 - Tangent are left.
Cosecant is positive so it can't be in quadrant 3.
Therefore, angle x is in Quadrant 2 or QII
Secant is hypotenuse / adjacent
5 = hypotenuse (hypotenuse is never a negative number)
-2 = adjacent
use pythagorean theorem to solve for opposite (bc tan = opp / adj)
tanx =
1:2! Is the answer to the question
We have to calculate the perimeter of the figure to the nearest tenth of a millimeter. This figure is made of a rectangle and a half of a circle. The first figure has the perimeter: 3 + 6 + 3 = 12 mm. The second figure has the perimeter: 2 * Pi * r / 2 = Pi * r ; and the radius : r = 6/2 = 3 mm. So Pi * 3 = 3.14 * 3 = 9.42. Fimally : 12 + 9.42 = 21.42 or 21.4 to the nearest tenth. Answer: C. 21.4 millimeters<span>. </span>