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Morgarella [4.7K]
3 years ago
6

5c-6=4-3c2c-6=42c=10c=5describe the error made in the problem.​

Mathematics
2 answers:
MatroZZZ [7]3 years ago
4 0

Answer:

The error is the problem 5c-6=4-3c.

Step-by-step explanation:

Because, it doesn't follow the rule c=5. All the problems need to abide by c=5. So the error is 5c-6=4-3c. If you do need to change it, you just need to change the 3c in the problem into -3c.

Basically the error is that the 3c in the problem is positive not negative.

Good luck! :D

SVETLANKA909090 [29]3 years ago
3 0

Answer:

5(c) - 6 = 4 - 3(c) is wrong

Step-by-step explanation:

The other problems are correct and equal. This one is wrong because when you do the equations you get 19 = -11 which is clearly not equal. You would need to change the equation to make it equal. So it would be:

5(c) - 6 = 4 - -3(c) so now it is 19 = 19.

So you would change 5(c) - 6 = 4 - 3(c)  into 5(c) - 6 = 4 - -3(c)

<em>I hope this helps :)</em>

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8n^2 multiplied by n^4
Aliun [14]

8n2*n4  

Final result :

 2^3n^6

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 2^3n^2 • n^4

Step  2  :

Multiplying exponential expressions :

2.1    n^2 multiplied by n^4 = n^(2 + 4) = n^6

Final result :

 2^3n^6

7 0
3 years ago
The original value of the car is $18,000 and it depreciates by 50% each year what is the value of the car after three years
Oksi-84 [34.3K]

value = 18000*(1-0.50)^3 = 2250

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8 0
3 years ago
Read 2 more answers
Simplify 2a^2b^3(4a^2+3ab^2-ab)
-BARSIC- [3]
2a^2b^3(4a^2+3ab^2-ab)=? 
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>

Substitute this back into the original equation and you get 
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) = 
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</span>
3 0
3 years ago
Given the coordinate points of the preimage, use the transformation given to provide the points of the image. W(3,3) V(3,4) U(5,
saw5 [17]

Answer:

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Step-by-step explanation:

The mapping for 90 degrees counterclockwise rotation is;

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The given points have coordinates: W(3,3) V(3,4) U(5,4)

(x,y)\to (-y,x)

This implies that:

W(3,3)\to W'(-3,3)

V(3,4)\to V'(-4,3)

U(5,4)\to U'(-4,5)

The required points of the image are:

W'(-3,3) V'(-4,3) U'(-4,5)

3 0
3 years ago
Which is the simplified from of p0
tiny-mole [99]
For this case we have the following expression:
p ^ 0
By properties of exponents we have:
Any number raised to the exponent zero is equal to one.
We have then, that applying this property:
p ^ 0 = 1
Answer:
the simplified form of p ^ 0 is:
D. 1
3 0
4 years ago
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