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3 years ago

5c-6=4-3c2c-6=42c=10c=5describe the error made in the problem.

Mathematics

2 answers:

MatroZZZ [7]3 years ago

4 0

Answer:

The error is the problem 5c-6=4-3c.

Step-by-step explanation:

Because, it doesn't follow the rule c=5. All the problems need to abide by c=5. So the error is 5c-6=4-3c. If you do need to change it, you just need to change the 3c in the problem into -3c.

Basically the error is that the 3c in the problem is positive not negative.

Good luck! :D

SVETLANKA909090 [29]3 years ago

3 0

Answer:

5(c) - 6 = 4 - 3(c) is wrong

Step-by-step explanation:

The other problems are correct and equal. This one is wrong because when you do the equations you get 19 = -11 which is clearly not equal. You would need to change the equation to make it equal. So it would be:

5(c) - 6 = 4 - -3(c) so now it is 19 = 19.

So you would change 5(c) - 6 = 4 - 3(c) into 5(c) - 6 = 4 - -3(c)

<em>I hope this helps :)</em>

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Select the equivalent expression.

Free_Kalibri [48]

Answer:

$\frac{7^{15}}{3^{30}}$

Step-by-step explanation:

The given expression is:

$(\frac{3^{-6}}{7^{-3}})^{5}$

Moving the expression to the other side in the fraction changes its sign to opposite. A numerator with negative exponent, when written in denominator will have the positive exponent. Using this rule, we can write:

$(\frac{3^{-6}}{7^{-3}})^{5}\\\\ = (\frac{7^{3}}{3^{6}} )^{5}$

The exponent 5 can be distributed to both numerator and denominator as shown:

$(\frac{7^{3}}{3^{6}} )^{5}\\\\ = \frac{(7^{3})^{5}}{(3^{6})^{5}}$

The power of a power can be written as a product. i.e.

$\frac{(7^{3})^{5}}{(3^{6})^{5}}\\\\ =\frac{7^{15}}{3^{30}}$

So, the expression similar to the given expression and with positive exponents is: $\frac{7^{15}}{3^{30}}$

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3 years ago

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5c-6=4-3c2c-6=42c=10c=5describe the error made in the problem.​

5c-6=4-3c2c-6=42c=10c=5describe the error made in the problem.