Answer:
Essentially additive editing and stringing “the good stuff” together, whereas subtractive is more about stringing all your raw footage together and “removing the bad stuff”
Additive editing feels confident and concerned with the pursuit of a specific, existing vision. And it’s faster. Subtractive editing feels like a deeper listening to what the footage is saying, and holding on to many potential permutations.
Explanation:
Addictive editing - creating a program from raw footage by starting by starting with nothing and adding selected components
Subtraction editing - creating a program by removing redundant or poor quality material from the original footage
The answer that best fits the blank is ISOLATED FROM. Those technology skills and subject-specific skills that are separated from the rest of the curriculum are being taught using the school computer laboratories. Technology skills include skills that use computers or machines such as web design, email management, database and spreadsheets, and etc.
Answer:
The answer is below
Explanation:
The amount of power dissipated by a processor is given by the formula:
P = fCV²
Where f = clock rate, C = capacitance and V = Voltage
For the old version of processor with a clock rate of f, capacitance C and voltage of V, the power dissipated is:
P(old) = fCV²
For the new version of processor with a clock rate of 20% increase = (100% + 20%)f = 1.2f, capacitance is the same = C and voltage of 20% increase = 1.2V, the power dissipated is:
P(new) = 1.2f × C × (1.2V)² = 1.2f × C × 1.44V² =1.728fCV² = 1.728 × Power dissipated by old processor
Hence, the new processor is 1.728 times (72.8% more) the power of the old processor
Answer:
Latency of an object O is shown below.
Explanation:
W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R
latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]
After combining the two case
latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]
where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.
server time for transmit the object is (K-1)[S/R +RTT - WS/R]
