The school has 550 students, 30 teachers, and 10 administrators. What is the ratio of teachers to students?

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

8 0

Answer:

$the \: second \: option \: is \: your \: answer \\ ratio \: of \: teacher \: to \: student \: is \\ no \: of \: teacher \: ratio \: no \: of \: students \\ 30 \: ratio \: 550 \\ divide \: both \: sides \: by \: 10 \\ 3 \: ratio \: 55$

Alik [6]3 years ago

6 0

Answer: 55:3

Step-by-step explanation:

550/10=55 <- students

30/10=3 <- Teachers

55:3 (last option) ||btw can u help me on my question?

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Can someone solve this

marysya [2.9K]

From the Arithmetic Information given, Pr = 0.049375 ≠ -8.050625 ≠ 0.0325 See explanation below.

<h3>

What are the step by steps solution to the questions above?</h3>

First, lets us restate the question properly. We have

Pr = 1 - ((6*12+6)/80)² = 1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) = 1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

Note that there are three equals signs. So lets divide the problem according and solve for the different parts.

Lets 1 - ((6*12+6)/80)² ............A

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) .............B; and

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6² ........C

Solving for A we have

1 - (78/80)²

= 1 - (0.975)²

= 1 - 0.950625

A = 0.049375

Solving for B we have

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400)

= 1- (14,256/1600) - (216/1600) - (36/6400)
= 1 - 8.91 - 0.135 - 0.005625

B = -8.050625

Solving for C we have

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

= 1 - 0.005625 * 144 - 0.001875 * 12 * 6 - 0.00015625 * 144

= 0.0325

In summary we can state that:

A = 0.049375

B = -8.050625

C = 0.0325

Given that there were no abstract quantities, we can state that

Pr = A ≠ B ≠C or

Pr = 0.049375 ≠ -8.050625 ≠ 0.0325

Learn more about equations with equal signs at

brainly.com/question/18924248
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2 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula