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Phantasy [73]
2 years ago
13

The Drombeg stone circle is a collection of megaliths (large prehistoric stones) located in Glandore, Ireland, that was used bet

ween 1100 BCE and 800 BCE.
The Drombeg stone circle measures approximately `31` ft across. Which of the following would be a reasonable approximation of its circumference?



A: 15.5
B: 49
C: 90
D: 97
E: 31π
Mathematics
2 answers:
anastassius [24]2 years ago
6 0
This answer to you’re question should be A. 15.5
disa [49]2 years ago
4 0

Answer:

A

Step-by-step explanation:

A is the reasonable answer

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A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0
3 years ago
Ellie takes her dog, Jack, for a 3 mile walk each day. On the first part of the walk, they go 2 mph. Then for the second part of
padilas [110]

Answer:

the entire walk is 9/7 hours i think

6 0
3 years ago
Someone please pass the answers to this
arsen [322]

Answer/Step-by-step explanation:

1. The figure is composed of a triangle and a rectangle.

Area of the triangle = ½*base*height

base = 4 ft

height = 12 - 8 = 4ft

Area of triangle = ½*4*4 = 8 ft²

Area of rectangle = length * width

Length = 8 ft

Width = 4 ft

Area of rectangle = 8*4 = 32 ft²

✔️Area of the figure = 8 + 32 = 40 ft²

2. The figure is composed of a semicircle and a triangle

Area of the semicircle = ½(πr²)

radius (r) = 3 cm

π = 3

Area = ½(3*3²) = 13.5 cm²

Area of triangle = ½*base*height

base = 3*2 = 6 cm

height = 6 cm

Area = ½*6*6 = 6 cm²

✔️Area of the figure = 13.5 + 6 = 19.5 cm²

5 0
2 years ago
What is the mean, median, mode, and range of 8, 35, 10, 12, 14?
Ivan

answer:

mean: 15.8

median: 12

mode: no mode

range: 27

step-by-step explanation:

  • first know how to find each of the above and what they are
  • mean = (avg) add all the numbers, then divide by the number of numbers
  • median = the middle number from increasing order
  • mode = the one that repeats the most
  • range = the difference between the largest and smallest number

8, 35, 10, 12, 14

<u>mean</u>

8 + 35 + 10 + 12 + 14 = 79

  • there are five numbers

79 / 5 = 15.8

<u>median</u>

  • put them from smallest to largest

8, 10, 12, 14, 35

  • 12 is the median OR the middle number

<u>mode</u>

  • no number repeat, so no mode

<u>range</u>

35 - 8 = 27

3 0
3 years ago
The ratio of the lengths of and is 2 : 1.
borishaifa [10]
The answer is 2 hopefully this helped
6 0
3 years ago
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