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Crank
3 years ago
15

X < 2 is the solution to which of the following compound inequalities?​

Mathematics
1 answer:
Anna35 [415]3 years ago
7 0

Answer:

  see below

Step-by-step explanation:

It works well to think about what these compound inequalities mean. One way to do that is to graph them, or to imagine what the graph of them looks like.

Since the result is a single inequality (x < 2), the compound will be "and" with x < 2 being more restrictive, or will be "or" with x < 2 being the least restrictive of completely overlapping inequalities.

Of the choices offered, C is the one of interest.

_____

<em>Comment on other choices</em>

A has all real numbers as solutions except in the range 2 ≤ x ≤ 3.

B has no solutions

C simplifies to x < 2 . . . . the one we want

D simplifies to x < 4

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Find the equation of the circle. With center at (-3, 1) and point on the circle= (5, -3).
patriot [66]

Answer:

(x + 3)² + (y - 1)² = 80

Step-by-step explanation:

Circle equation: (x - h)² + (y - k)² = r²

We are given <em>h</em> and <em>k</em>, so we just plug that in:

(x + 3)² + (y - 1)² = r²

To find <em>r</em>, we need to use distance formula: d = \sqrt{(x2-x1)^2+(y2-y1)^2} between the center of the circle and the point on the circle. We should get √80 as <em>r</em>. We plug that in to get our answer:

(x + 3)² + (y - 1)² = 80

3 0
3 years ago
What is the slope of this line?<br> 6<br> 10
AleksAgata [21]

Answer: 0.6

Step-by-step explanation:

m = 6/10

m = 0.6

5 0
2 years ago
Rewrite the expression (19x3 – 5x2 + 6x – 2)/(x + 1) in the form q(x) + r(x)/b(x) where q(x) = quotient, r(x) = remainder, and b
wolverine [178]

We are asked to perform the long division on the following expression.

\frac{(19x^3-5x^2+6x-2)}{(x+1)}

Let us perform the long division.

So, we have

Quotient: q(x) = 19x^2 - 24x + 30

Remainder: r(x) = -32

Divisor: b(x) = x + 1

Therefore, the equivalent expression is

19x^2-24x+30-\frac{32}{(x+1)}

The 3rd option is the correct answer.

7 0
1 year ago
In how many ways can a set of two nonnegative integers less than 100 be chosen?
hichkok12 [17]

Answer: 4950

Step-by-step explanation:

The number of possible combinations of n things taken r at a time is given by :-

C(n,r)=\dfrac{n!}{r!(n-r)!}

Total nonnegative integers less than 100 ={0,1,2,... ,99} = 100

So, the number of combinations of choosing 2 out of them = C(100,2)=\dfrac{100!}{2!98!}=\dfrac{100\times99\times98!}{2\times98!}\\\\=\dfrac{100\times99}{2}\\\\=50\times 99\\\\=4950

So, the number of ways to choose a set of two nonnegative integers less than 100 = 4950

5 0
3 years ago
1+1+1+9+9+3=q which is q
EastWind [94]

Answer:

24.

Step-by-step explanation:

1 + 1 + 1 = 3

9 + 9 = 18

3 + 18 = 21 + 3 = 24

I hope this helps, have a nice day.

6 0
3 years ago
Read 2 more answers
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