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ANTONII [103]
2 years ago
5

TRUE OF FALSEEEEEEEEEESSSSSSSSSSSSSS

Mathematics
1 answer:
horrorfan [7]2 years ago
7 0
ITS FALSE HELLLLLOOO
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3 years ago
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This is the question: Write down the equation of a circle with centre (0,0) and radius 5.
ANTONII [103]
You almost had it right! remember the equation of a circle is
(x - h)^2 + (y - k)^2 = r^2. the center is (h,k) and r is the radius.

(x - 0)^2 + (y - 0)^2 = 5^2

x^2 + y^2 = 25 <<< your answer

hope that helps, God bless!
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3 years ago
If 3 dozen cookies require 1 cup of sugar, write a direct variation equation in two variables that represent this situation. Mak
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Step-by-step explanation:

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3 years ago
In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th
olya-2409 [2.1K]

Answer:

\frac{BE}{EC} =\frac{1}{3}

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

\frac{BK}{CK} =\frac{1}{4}

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE                ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE     ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK  and Δ EBK are similar

so we have

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\frac{AD}{BE} =\frac{4}{1}

\frac{BC}{BE}=\frac{4}{1}     ( ABCD is parallelogram so AD=BC)

\frac{BE+EC}{BE}=\frac{4}{1}         ( BC= BE+EC)

\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}

1+\frac{EC}{BE}=4

\frac{EC}{BE}=3  ( subtracting 1 from both side )

\frac{EC}{BE}=\frac{3}{1}

taking reciprocal both side

\frac{BE}{EC} =\frac{1}{3}


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3 years ago
Write the equation of the line that passes through the points (-9,2) and (-2,8).
tresset_1 [31]

Answer:

y = 6/7x + 68/7

Step-by-step explanation:

5 0
3 years ago
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