Find the other endpoint of the line segment with the given endpoint and midpoint. Endpoint: (-8,8) Midpoint: (5,-3)

1 answer:

4 0

Take a look at the x-coordinates of the two given points: -8 and 5. If we depart from the left endpoint (-8,8) to the right in the direction of the midpoint (5,-3), we see that x increases by 13 as we approach the midpoint. The other endpoint is twice as far (26 units instead of 13 units) from the first one. Thus, the x-coordinate of the right endpoint is 5+13, or 18.

Take similar actions withe the y-coordinates. From y = 8 at the left endpoint, we end up at y = -3 at the midpoint, a decrease in y of 11. Decrease y again by 11 from the midpoint y-coordinate, -3, ending up with -14.

The right endpoint is thus (18, -14).

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OlgaM077 [116]

Answer:

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Step-by-step explanation:

The theoretical probability of getting a even number is 1/2 because it equally likely to get and not to get it. Since half of the numbers are even then the probability of getting an even is 1/2.

6 0

2 years ago

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Write the equation of a circle with a center at (1, 4) where a point on the circle is (4, 8).

mina [271]

Notice the picture below

$\bf \textit{equation of a circle}\\\\
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad center\ ({{ h}},{{ k}})\qquad
radius={{ r}}\\\\
-----------------------------\\\\
\textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ 4}})\quad 
% (c,d)
&({{ 4}}\quad ,&{{ 8}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\leftarrow r$

you have the center, the h,k, all you really need is the radius "r"