Question

Which equation models the linear relationship between the variables shown in the table?

Answer 1

Answer:

H)  y = 2x -3

Step-by-step explanation:

Given the data on the table for the values of 'x' and 'y', you can find the slope by taking two points and subtracting the difference in 'y' values from the difference in 'x' values:

($(x_{1},y_{1})and(x_{2},y_{2})=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Using points (6, 9) and (2, 1):  $\frac{9-1}{6-2}=\frac{8}{4}=2$

Given the slope (m)=2, you can use slope-intercept form to solve for 'b':

y = mx + b

y = 2x + b, use point (2, 1) for 'x' and 'y':  1 = 2(2) + b or 1 = 4 + b so b = -3

Put the values of m = 2 and b = -3 into your slope-intercept form:

y = 2x -3 (answer H)