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Dmitrij [34]
3 years ago
13

-6x+5y=9 in standard form??

Mathematics
2 answers:
earnstyle [38]3 years ago
7 0
The awnser is 6x-5y=_9
Murljashka [212]3 years ago
6 0
Negative six x plus five y equals nine
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What is the area of the pool ?
Lostsunrise [7]

Answer:

brainly.com/question/24258518

Step-by-step explanation:

3 0
3 years ago
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PLEASE HELP WILL MARK AS BRAINLIEST IF YOU ANSWER FIRST!!!!!!
vampirchik [111]
A + C
(-5, -7) is 7 units to the left of point H
(-7, 7) is more than 7 units up and left of point H
the x axis is at (infinity, 0), being only 7 points up from point H
4 0
2 years ago
X + 20 is greater than 4x -1
Paul [167]

Answer:

False; they are equal.

Step-by-step explanation:

The equation is x + 20 > 4x - 1.

First, do the opposite of -1 and add one to the other side while -1+1 cancels out. Now it's x+21 > 4x. Now subtract x from both sides. Positive x minus negative x cancels out and 4x minus x or 1x is 3x. Now you're left with 21> 3x. Now do the inverse operation of multiplication and divide both sides by 3. Now the 3x over 3 cancels out and 21 divided by 3 is 7. So x is 7. If you substitute it in. It will be 7+20 which is 27 which is great than 4(7)-1 which is 28-1. 28-1 is 27. So, the equation is false. They are equal.

7 0
3 years ago
Which two ratios form a proportion? A 1/ 2 and 4/2 B.2/1 and 4/8 C.1/2 and 8/4 D.2/1 and 16/8
wel

Two ratios form a proportion if they are equal. If one fraction is equivalent to the other fraction, they form a proportion. To find out, reduce both fractions and see if they are equal.

A

1/2 and 4/2

Reduce 4/2 to 2/1.

1/2 and 2/1 are not equal.

1/2 and 4/2 do not form a proportion.

B

2/1 and 4/8

Reduce 4/8 to 1/2.

2/1 and 1/2 are not equal.

2/1 and 4/8 do not form a proportion

C

1/2 and 8/4

Reduce 8/4 to 2/1.

1/2 and 2/1 are not equal.

1/2 and 8/4 do not form a proportion

D

2/1 and 16/8

Reduce 16/8 to 2/1

2/1 and 2/1 are equal.

2/1 and 16/8 form a proportion.

Answer: D. 2/1 and 16/8

4 0
3 years ago
Read 2 more answers
The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find
Serga [27]

Answer:

Required solution is y(x)=1+A\cos x+B\sin x where A and B are constants.

Step-by-step explanation:

Given nonhomogenous differential equation is,

y''(x)+y'(x)=1\hfill (1)   with y_1(x)=1

To find another solution, consider m=\frac{\partial}{\partial x} be such that,

m^2+1=0\implies m=\pm i

Hence,

C.F=A\cos x+B\sin x   where A and B are constants.

Let  D=\frac{\partial}{\partial x}

P.I=\frac{1}{1+D^2}(1)

=(1+D^2)^{-1}(1)

=(1-D^2+.....)(1)=1

Hence,

y(x)=1+A\cos x+B\sin x where A and B are constants.

which is required solution.

6 0
3 years ago
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