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2 years ago

Resolve into factors. px + qx + py + qy (algebra).

Mathematics

2 answers:

mamaluj [8]2 years ago

6 0

Answer:

(p+q)(x+y)

HOPE IT HELPS YOU.....

amm18122 years ago

5 0

Step-by-step explanation:

we want to factor the following expression

$\displaystyle px + qx + py + qy$

to do so group px's and qy's

$\displaystyle px + py + qx + qy$

factor out p:

$\displaystyle p(x + y ) + qx + qy$

factor out "q":

$\displaystyle p(x + y ) + q(x + y)$

group:

$\boxed{ \displaystyle( p+ q)(x + y)}$

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What two numbers add to -5 and multiply to 12?

Deffense [45]

Negative 6 and negative 2

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3 years ago

Read 2 more answers

Select True or false for each statement

PilotLPTM [1.2K]

Answer:

False

True

False

Step-by-step explanation:

1. We have to get the sum as follows :

$3\frac{4}{9} + 4\frac{6}{9}$

= $\frac{31}{9} + \frac{42}{9}$

= $\frac{31 + 42}{9}$

= $\frac{73}{9}$

= $8\frac{1}{9} \neq 7\frac{1}{9}$

So, this is false.

2. We have to get the sum as follows :

$4\frac{5}{6} + 1\frac{3}{6}$

= $\frac{29}{6} + \frac{9}{6}$

= $\frac{29 + 9}{6}$

= $\frac{38}{6}$

= $6\frac{2}{6}$

So, this is true.

3. We have to get the difference as follows :

$4\frac{5}{8} - 2\frac{4}{8}$

= $\frac{37}{8} - \frac{20}{8}$

= $\frac{37 - 20}{8}$

= $\frac{17}{8}$

= $2\frac{1}{8} \neq 2\frac{3}{8}$

So, this is false.

4. We have to get the difference as follows :

$7\frac{5}{8} - 4\frac{2}{8}$

= $\frac{61}{8} - \frac{34}{8}$

= $\frac{61 - 34}{8}$

= $\frac{27}{8}$

= $3\frac{3}{8} \neq 3$

So, this is also false. (Answer)

5 0

3 years ago

17. Simplify (3 × 22) ÷ 6 + [28 – (4)2] = ?

Effectus [21]

Answer:

Step-by-step explanation:

(3*22=66) / 6 + [28n - (4)2=20]

66 /6 = 11+ [20]

11+20= 31

7 0

3 years ago

Find the value of c that completes the square

Kitty [74]

Answer:

c = 64

Step-by-step explanation:

Given

x² - 16x + c

To complete the square

add ( half the coefficient of the x- term )² to x² - 16x

x² + 2(- 8)x + 64

= (x - 8)²

Thus

x² - 16x + 64 = (x - 8)² ← a perfect square

with c = 64

8 0

2 years ago

Select the values that make the inequality h < 2 true.

weqwewe [10]

Given:

The inequality is:

$h\leq 2$

To find:

The values that make the given inequality true.

Solution:

We have,

$h\leq 2$

It means the value of h must be less than or equal to 2.

In the given options, the list of numbers which are less than or equal to 2 is

-6, -3, -1, 1, 1.9, 1.99, 1.999, 2

The list of numbers which are greater than 2 is

2.001, 2.01, 2.1, 3, 5, 7, 10

Therefore, the first 8 options are correct and the required values are -6, -3, -1, 1, 1.9, 1.99, 1.999, 2.

3 0

2 years ago

Resolve into factors. px + qx + py + qy (algebra). ​

Resolve into factors. px + qx + py + qy (algebra).