The equation of a cricle passing through (h,h) and with radius r is
so
cente ris (-6,7) and passing through (4,-2)
subsitute (4,-2) to find r^2
so it is
A is the answer
Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
95°
Step-by-step explanation:
Angle 1 and 4 are opposite angles, thus equal, so:
3x+10 = 4x-15 =>
x = 25
Angle 1 and 4 are 85°
Angle 4 and angle 6 are called allied (or co-interior) angles, which are supplementary, i.e., angle 6 = 180 - angle 4, so angle 6 = 95°.
Angle 6 and 7 are again opposite, so angle 7 is 95° as well!
(4,-1) turns into (1,4) because the equation for that is (x,y)->(y•-1,x)
Answer:
Number of 1 $ bill = 20
Number of 5 $ bill = 6
Explanation:
Let p represent number of one dollar bolls and q represent number of five bills.
A total of 26 bills are in a cash box.
p + q = 26 ------------------------- Equation 1
The total amount of cash in the box is $50
p + 5q = 50 ------------------------- Equation 2
Equation 2 - Equation 1,
p + 5q - p -q = 50 - 26
4q = 24
q = 6
Substituting in equation 1.
p + 6 = 26
p = 20
Number of 1 $ bill = 20
Number of 5 $ bill = 6
