Answer:
X 1 2 3 4 5 6
P(X) 0.115 a 0.422 0.312 0.034 0.015
If we want a probability distribution we need to satisfy two important conditions:
1)
2)
And using the second condition we have this:
With a the probability associated with the value of X=2 and solving for a we got:
So then for this case
Step-by-step explanation:
Let X the random variable that represent the number of classes that a student takes
For this case we have the following probability distribution given:
X 1 2 3 4 5 6
P(X) 0.115 a 0.422 0.312 0.034 0.015
If we want a probability distribution we need to satisfy two important conditions:
1)
2)
And using the second condition we have this:
With a the probability associated with the value of X=2 and solving for a we got:
So then for this case