Answer:
Correct choice is
Step-by-step explanation:
1. If then you can find the inverse
2. If then
3. Hence,
There are 8 math classes in 7th grade.
1 answer:
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Answer:
a) Null hypothesis:
Alternative hypothesis:
b)
The degrees of freedom are given by:
The p value for this case taking in count the alternative hypothesis would be:
Step-by-step explanation:
Information given
represent the sample mean for the amount spent each shopper
represent the sample standard deviation
sample size
represent the value to verify
t would represent the statistic
represent the p value f
Part a
We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic for this case would be given by:
(1)
Replacing the info given we got:
The degrees of freedom are given by:
The p value for this case taking in count the alternative hypothesis would be:
Answer:
Step-by-step explanation:
Hello!
The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.
To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.
Then the study variable is
X: calories of a 6 serve sample of the new reduced-calorie version. (cal)
The variable has a normal distribution with a population standard deviation of 0.82 cal.
To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:
H₀: μ ≥ 60
H₁: μ < 60
α: 0.01
Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal
This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.
If Z ≤ -2.334, the decision is to reject the null hypothesis.
If Z > -2.334, the decision is to not reject the null hypothesis.
Using the data of the sample I've calculated the sample mean.
X[bar]= ∑X/n= 1548.61/26= 59.56 cal
The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.
At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.
I hope it helps!
