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love history [14]
3 years ago
11

GUY'S I need HELP PLEASE!!!!

Mathematics
1 answer:
natulia [17]3 years ago
3 0
A.
Because negative multiplied by negative is positive
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Hey bakery display Easter cookies equally on seven trays if there are 567 cookies how many cookies are on each tray
vivado [14]

Answer: 81 cookies per tray


Step-by-step explanation:

567/7= 81


7 0
4 years ago
What is the vertex of f (x) = 5x^2+20x-16
sergeinik [125]

Answer:

vertex = (- 2, - 36)

Step-by-step explanation:

Given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

f(x) = 5x² + 20x - 16 is in standard form

with a = 5, b = 20 and c = - 16

x_{vertex} = - \frac{20}{10} = - 2

Substitute x = - 2 into f(x) for corresponding y- coordinate

f(- 2) = 5(- 2)² +20(- 2) - 16 = 20 - 40 - 16 = - 36

vertex = (- 2, - 36)



3 0
3 years ago
Read 2 more answers
What is a solution for 11/12
elena-s [515]

Answer:

It is either 11/12 or 0.91666666667.....

Step-by-step explanation:

Because this can not be actually divided into a "number" like 2 or 5, we can only get a approximate. Like the top answer.

Round to the nearest ten is 0.9

Round it to nearest hundredths is 0.92

7 0
3 years ago
What is the value of the exponential expression 24?<br> O A. 8<br> B. 32<br> O C. 64<br> O D. 16
adelina 88 [10]

Answer:

16

Step-by-step explanation:

2^4 is the same thing as 2*2*2*2*2. 2 times 2 is 4, times 2 is 8, times 2 again is 16.

4 0
2 years ago
Add the two equations, 0.75x+1.5y=40 and −1.5x−1.5y=−60 , to find the value of x .
sergij07 [2.7K]

The value of x in the equation is 26.7

<h3>How to solve an equation?</h3>

0.75x + 1.5y = 40

−1.5x − 1.5y = −60

add both equation to eliminate y .

Therefore,

−1.5x + 0.75x = -0.75x

1.5y + (- 1.5y) = 0

40 + (-60) = -20

Hence,

-0.75x  = - 20

divide both sides by -0.75

-0.75x / -0/75 = - 20 / -0.75

x = - 20 / -0.75

x = 26.6666666667

x = 26.7

learn more on equation here:  brainly.com/question/7234676

#SPJ1

7 0
1 year ago
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