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4 years ago

Is subtraction associated in rational number ? explain with an example.

Mathematics

1 answer:

JulsSmile [24]4 years ago

8 0

Answer:

No, subtraction is NOT associative in rational numbers.

Step-by-step explanation:

Step-by-step explanation: We are asked to state whether subtraction is associative in rational numbers or not. To explain with an example. The subtraction is NOT associative in rational numbers.

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Which value of x is a solution of x < -2? A. -3 B. -2 C. -1 D. 0

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Answer:

Step-by-step explanation:

-3<-2

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3 years ago

What is importance of banks to ecomics

defon

Answer:

They do transactions from such a large distance

Step-by-step explanation:

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3 years ago

General solutions of sin(x-90)+cos(x+270)=-1 {both 90 and 270 are in degrees}

mixer [17]

Answer:

$\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

Step-by-step explanation:

Given:

$\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1$

First, note that

$\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x$

So, the equation is

$-\cos x+\sin x= -1$

Multiply this equation by $\frac{\sqrt{2}}{2}:$

$-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}$

The general solution is

$x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.$

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4 years ago

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Answer:

Same in both sets

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Different

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Cannot tell

mode, mean

Step-by-step explanation:

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3 years ago

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Each one cost $3.49

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3 years ago

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Is subtraction associated in rational number ? explain with an example.​

Is subtraction associated in rational number ? explain with an example.