The way you put it is confusing. I'll answer but the way you put it was confusing to me.
Answer:
sin θ = 15/17
Step-by-step explanation:
First we have to know how much the hypotenuse measures.
to take out the hypotenuse we will use pitagoras, with the following formula.
h^2 = c1^2 + c2^2
c1 = 8
c2 = 15
h^2 = 8^2 + 15^2
h^2 = 64 + 225
h = √ 289
h = 17
well to start we have to know the relationships between angles, legs and the hypotenuse.
a: adjacent
o: opposite
h: hypotenuse
sin θ = o/h
cos θ= a/h
tan θ = o/a
we want to know the sin of θ
sin θ = o/h
sin θ = 15/17
6h + 5h - 3j = 11h - 3j (all u can do is combine like terms...if they're not like terms, they cannot be combined)
It is really easy it is 6
