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Fittoniya [83]
3 years ago
5

Parallel to y= -2x + 3 passes through the point (-2, -1)

Mathematics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

y = -2x - 5

Step-by-step explanation:

An equation of a line in slope-intercept is y=mx + b.

x and y are points on the line.

m is the slope.

b is the y-intercept.

To find this equation, we will need to find m and b.

When lines are parallel, they have the same slope.

A line parallel to y = -2x + 3 has a slope of -2.

m = -2

To find b, substitute into the equation a point on the line (-2, -1) and m = -2.

A point is in the form (x, y). So x = -2, y = -1.

y = mx + b

-1 = (-2)(-2) + b  Simplify by multiplying the (-2)(-2)

-1 = 4 + b   Subtract 4 from both sides to isolate b

-5 = b

b = -5   Writing the variable on the left side is standard formatting

Since we now know the y-intercept, b= -5, and the slope, m = -2, substitute them into y=mx + b to get the equation of the line.

y = -2x - 5

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The quotient is 3x - 11 + 60/(x + 5) ⇒ 2nd answer

Step-by-step explanation:

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∴ 3x (x + 5) = 3x² + 15x

-Subtract this expression from the dividend

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- Divide the first term -11x in the new dividend by the first

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∴ -11x ÷ x = -11

- Multiply the divisor by -11

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5 0
3 years ago
Please help me! 7 points!! I don’t understand
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This is adding two vectors, one magnitude 300 direction east, and one magnitude 100 direction 30 degrees northeast.

For the resulting sum we can use the Law of Cosines or just add up the components.  Let's try it both ways.

Components first.   In the east direction we have

300 + 100 cos 30° = 300 + 100(√3/2) = 386.60 miles per hour

In the north direction we have

0 + 100 sin 30° = 100 (1/2) =  50 miles per hour

So a total speed of

sqrt{386.6^2 + 50^2} = 389.82 miles per hour

Answer: 389.82

--------

OK let's try the Law of Cosines.   We have sides 300 and 100 and included angle 150°.

c^2 = 300^2 + 100^2 - 2 (300)(100) \cos 150^\circ

c=\sqrt{151961.52422} = 389.82 \quad\checkmark

5 0
3 years ago
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