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butalik [34]
3 years ago
10

What is 189÷6 with a remainder?

Mathematics
2 answers:
Umnica [9.8K]3 years ago
5 0
189 divide by 6 is 31.5
nasty-shy [4]3 years ago
3 0
The remainder is 3. :)) tell me if you need a explanation.
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538X46 answer this in estimate
masya89 [10]
24748 thts what I think
6 0
4 years ago
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A sailboat travels a distance of 2 1/2 miles in 1/6 of an hour. Which complex fraction represents the unit rate in miles per hou
Nikitich [7]
At first glance, prolly c
3 0
3 years ago
In one year the perseid metor shower had a metor appear every 1/5 5 minutes on average That same year the Leonid metor shower ha
olga55 [171]

In one year, the Perseid meteor shower had a meteor appear every 1 1/5 minutes on average. That same year, the Leonid meteor shower had a meteor appear every 4 2/3 minutes on average. How many more meteors fell during the Perseid meteor shower?

Answer:

325,452 meteors

Step-by-step explanation:

We all know that :

We have 365 days in a year and in each day there are 24 hours, Likewise an hour has 60 minutes

SO, the total number of minutes in a year is :

365 × 24 × 60 = 525600 minutes

For Perseid  meteor:

1 + \frac{1}{5}  \\ \\ = 1 + 0.2 \\  \\ = 1.2

So one meteor fall at 1.2 minutes interval Thus, in a year, we will have :

1 meteor - 1.2 minutes.

x meteor - 525600 minutes.

1.2x = 525600

x = \frac{525600}{1.2}

x = 438000

∴  438,000 meteors fell during the Perseid shower.

For  Leonid meteor shower:

4 + \frac{2}{3} = 4.67

So one meteor fall at 4.67 minutes interval Thus, in a year, we will have :

1 meteor - 4.67 minutes.

x meteors - 525600 minutes.

4.67x = 525600

x = \frac{525600}{4.67}

x = 112548

112,548 meteors fell during the Leonid Shower.

Finally , the numbers of more meteors that  fell during the Perseid meteor shower is calculated by the difference in the number of Perseid meteor shower and Lenoid meteor shower. i.e

438,000 - 112,548 = 325,452

325,452 more meteors fell during the Perseid meteor shower

5 0
3 years ago
A) Write the following in standard form and find A, B and C
alex41 [277]

Answer:

  • a)  2x -y = -5; A=2, B=-1, C=-5
  • b)  y = 2x +5

Step-by-step explanation:

a) Standard Form is ...

  Ax + By = C

where A > 0 and A, B, C are mutually prime.

To get that form, we can add 2x-5 to both sides of the equation:

  (2x -5) -2x = (2x -5) -y +5

  -5 = 2x -y

Then we can swap sides of the equal sign:

  2x -y = -5 . . . . . . standard form

Matching this to the generic standard form equation, we find ...

  A = 2

  B = -1

  C = -5

__

b) We can solve for y by adding 2x+y to both sides of the equation:

  (2x +y) -2x = (2x +y) -y +5

  y = 2x +5 . . . . . . slope-intercept form

5 0
3 years ago
How do you write 4 13/20 as a decimal
yaroslaw [1]
4.65

I hope I helped you 
5 0
3 years ago
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