PLS HELP ME AS QUICK AS POSSIBLE,
THANKS :)) I'm a bit confused
Can you answer 1 and 2, then confirm 3 :))))
Answer:
Explanation: Two possible solutions
in the absence of friction
mgh = ½mv²
h = v²/2g = 24.4²(2(9.81) = 30.344... = 30.3 m
if enough rolling friction exists to keep the ball from sliding, but ignoring air resistance and assuming the ball is already rolling smoothly at the start
mgh = ½mv² + ½Iω²
mgh = ½mv² + ½((2/3)mR²)(v/R)²
2gh = v² + (2/3)v²
2gh = (5/3)v²
h = (5/6)v²/g
h = (5/6)24.4²/9.81 = 50.5742 = 50.6 m
Answer:
1 and 3
Explanation:
At the point of hitting the tennis ball by the racquet, the force by the hit is acting on the ball.
Since there is a strong wind, the force exerted by the air will act on the tennis ball as it journeys to the ground in the opponents court.
Also, since the tennis ball undergoes a downward motion before it touches the ground, a downward force of gravity also acts on the ball.
After the tennis ball has left contact with the racquet, the force by the hit ceases to act on the ball since they are no longer in contact. However, <em>the downward force of gravity and the force exerted by the air still act on the tennis ball before it touches the ground. </em>
Therefore, the correct choice is:
1 and 3
Answer:
7.5 seconds
Explanation:
because wattsXtime=Joules so 120X__=900. 900 divided by 120= 7.5