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Lapatulllka [165]
3 years ago
11

A 75-kg man is riding in a 30-kg cart at 2.0 m/s. He jumps off in such a way as to land on the ground with no horizontal velocit

y. The resulting change in speed of the cart is:
Physics
1 answer:
Valentin [98]3 years ago
4 0

Answer:

Explanation:

We shall apply law of conservation of momentum .

M and m be mass of man and boat . V and v be velocity of man and boat .

MV = mv

75 V = 30 v

2 .0 m/s is relative velocity of man wrt boat .

Given v + V = 2

V = 2 - v

75 ( 2 - v )  = 30 v

150 - 75 v = 30 v

150 = 105 v

v = 1.43 m /s

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A student uses a spring loaded launcher to launch a marble vertically in the air. The mass of the marble is
GarryVolchara [31]

Answer:

Part a)

When spring compressed by 2 cm

H = 1.47 m

Part b)

When spring is compressed by 4 cm

H = 5.94 m

Explanation:

Part a)

As we know that the spring is compressed and released

so here spring potential energy is converted into gravitational potential energy at its maximum height

So we will have

\frac{1}{2}kx^2 = mg(H + x)

0.5(220)(0.02)^2 = 0.003(9.81)(H + 0.02)

so we have

H = 1.47 m

Part b)

Similarly when spring is compressed by 4 cm

then we have

\frac{1}{2}kx^2 = mg(H + x)

0.5(220)(0.04)^2 = 0.003(9.81)(H + 0.04)

so we have

H = 5.94 m

8 0
4 years ago
A crane carries a 1600 kg car at 1.5 m/s^2 with a chain that has a negligible mass. If the coefficient of kinetic friction betwe
padilas [110]

Answer:

option (d) 7.1 kN

Explanation:

Given:

Mass of the car, m = 1600 kg

Acceleration of the car, a = 1.5 m/s²

Coefficient of kinetic friction = 0.3

let the tension be 'T'

Now,

ma = T - f .................(1)

where f is the frictional force

also,

f = 0.3 × mg

where g is the acceleration due to the gravity

thus,

f = 0.3 × 1600 × 9.81 =

therefore,

equation 1 becomes

1600 × 1.5 = T - 4708.8

or

T = 2400 + 4708.8

or

T = 7108.8 N

or

T = 7.108 kN

Hence,

The correct answer is option (d) 7.1 kN

6 0
3 years ago
ANSWER ASAPPP
Vikki [24]
C) fault block, the mountain is forming on a FAULT line.
5 0
3 years ago
Read 2 more answers
A charge q = 2.00 μC is placed at the origin in a region where there is already a uniform electric field = (100 N/C) î. Calculat
SVETLANKA909090 [29]

Answer:

\phi = 2.26 \times 10^5 Nm^2/C

Explanation:

Due to uniform electric field net flux through a closed surface is always zero

so here we have to find the net flux through a sphere due to a point charge placed at origin and due to a uniform electric field

so here we will have

\phi = \frac{q}{\epsilon_o}

now we have

\phi = \frac{2 \times 10^{-6}}{8.85 \times 10^{-12}}

\phi = 2.26 \times 10^5 Nm^2/C

Due to external uniform field the electric flux is zero

so the total flux is only due to charge and it is equal to

\phi = 2.26 \times 10^5 Nm^2/C

3 0
3 years ago
A baseball has a mass of 145 g. A pitcher throws the baseball so that it accelerates at a rate of 80 m/s2 How much force did the
Katena32 [7]

Answer:

<h2>11.6 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

mass is in kg

1000 g = 1 kg

145 g = 0.145 kg

From the question we have

force = 0.145 × 80

We have the final answer as

<h3>11.6 N</h3>

Hope this helps you

6 0
3 years ago
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