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almond37 [142]
2 years ago
13

What is -2 1/4 + 5 1/2 ?

Mathematics
1 answer:
Fofino [41]2 years ago
8 0
To first find the answer to this, let's find a common denominator between each fraction. The denominator is the bottom number of a fraction.
To find the common denominator, let's factor out each of our denominators 5 times to see if they have a common number.
4: 4, 8, 12, 16, 20
2: 2, 4, 6, 8, 10
They both appear to have the smallest common denominator of 4, so let's use 4.

We already have 1/4 with a denominator of 4, but not 1/2.
2 x 2 = 4, so multiply the numerator and the denominator of 1/2 by 2.
1 x 2 = 2
2 x 2 = 4
Your new fraction is 2/4.

Our expression now is:
-2 1/4 + 5 2/4
or (in simpler terms)
5 2/4 - 2 1/4

Subtract the fractions first.
2/4 - 1/4 = 1/4

Now subtract the whole numbers.
5 - 2 = 3

You are left with:
3 1/4

I hope this helps!
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Answer: v=0

Step-by-step explanation:

Because....

Step 1: Simplify both sides of the equation.

−v+ 1= 8v + 1

Step 2: Subtract 8v from both sides.

−v+1 − 8v = 8v+1 − 8v

−9v + 1 = 1

Step 3: Subtract 1 from both sides.

−9v + 1 −1 = 1−1

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Step 4: Divide both sides by -9.

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What is the y- intercept of the function described in the table x: 1,2,3,4 y: 8,6,4,2
weeeeeb [17]

Answer:

The y-intercept of the function is: b=10

Step-by-step explanation:

Given the table

x                 y

1                 8

2                6

3                4

4                2

Taking any two points to find the slope

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  • (2, 6)

The slope between (1, 8) and (2, 6) is:

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(1,\:8\right),\:\left(x_2,\:y_2\right)=\left(2,\:6\right)

m=\frac{6-8}{2-1}

m=-2

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Substituting m=-2 and any point i.e. (1, 8) in the slope-intercept form of the line equation to find the y-intercept (b).

y=mx+b

8 = -2(1) + b

8 = -2 + b

b = 8+2

b = 10

Thus, the y-intercept of the function is: b=10

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Where is the axis on a quadrant
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