Bonn. H j j I in j.
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You're given two points for f(t) and g(t) each. Two points, (x1,y1), and (x2,y2). In this case, x1 is always x1=0, since the time t starts counting at the earliest year given.
We know the form y=mx+b. m can be found a la (y2-y1)/(x2-x1), but remember x1 is 0. b can be found at f(0) or g(0), which we're already given; y1 for both cases.
I'm sorry, but I'm not giving a direct answer. Knowing the method, and being careful with calculations, should be more than sufficient.<span>it would be 22395-20808/5=317.4 f(t)
26508-26155/5= 70.6
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The answer is 28 for this equation
Answer:
Marcus has 494 cards.
Jorge has 988 cards.
Ren has 518 cards.
Step-by-step explanation:
Let x represent Marcus's cards.
M + J + R
(x) + (2x) + (x+24) = 2000
x + 2x + x + 24 = 2000
4x +24 =2000
4x = 1976
x = 494
