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3 years ago

What is the solution for the system of equations? Use the substitution method to solve. 2x+y=20

Mathematics

1 answer:

slava [35]3 years ago

5 0

2x + y = 20

-5y = -6x + 12

To use the substitution method, first isolate one of the variables in one of the equations.

Isolate the "y" in the first equation (because it is the easiest to isolate), and substitute it into the second equation:

2x + y = 20 Subtract 2x on both sides

y = 20 - 2x

-5y = -6x + 12 (since y = 20 - 2x, you can substitute 20 - 2x into y)

-5(20 - 2x) = -6x + 12 Multiply -5 into (20 - 2x)

-100 + 10x = -6x +12 Add 100 on both sides

10x = -6x + 112 Add 6x on both sides

16x = 112 Divide 16 on both sides

x = 7

Now that you have found x, you can substitute 7 into x for one of the original equations:

2x + y = 20

2(7) + y = 20

14 + y = 20 Subtract 14 on both sides

y = 6

-5y = -6x + 12

-5y = -6(7) + 12

-5y = -42 + 12

-5y = -30 Divide -5 on both sides

y = 6

x = 7, y = 6

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1. Some numbers, such as $\frac{1}{10}$ , have a decimal expansion that terminates.

2. All real numbers have a decimal expansion.

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1. Some numbers, such as $\frac{1}{10}$ , have a decimal expansion that terminates.

It is correct as the decimal expansion of $\frac{1}{10}$ is 0.1, which terminates.

2. All real numbers have a decimal expansion.

This is also correct as both rational and irrational numbers can be written in decimal form.

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4. Only some real numbers have a decimal expansion.

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5. Some numbers, such as $\frac{1}{18}$ , have a decimal expansion that repeats but does not terminate.

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