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3 years ago

What are some helpful tricks to know when solving non homogenous second order differential equation

Mathematics

1 answer:

DiKsa [7]3 years ago

4 0

Science is the answer

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Rational root theorem <br><br><br> f(x) = 2x4 – 9x2 +7

IRISSAK [1]

Answer: ±1,±1/2,±7,±7/2

Step-by-step explanation:

Hope this helps!

8 0

2 years ago

complete the steps to demonstrate why you multiply by the reciprocal when dividing fractions. Find 1/4 divided by 3/8

LuckyWell [14K]

Multiplying is the opposite of dividing, so that's why you multiply it by the reciprocal.
1. 1/4 ÷ 3/8 is equivalent to 1/4 × 8/3
2. 1/3 × 8/3 = ?
3. 1 × 8 = 8
4. 3 × 3 = 9

4 0

3 years ago

Explain how knowing that 5/8=.625 helps you write the decimal for 4 5/8

Paul [167]

Because since we know that 5/8 = .625, instead of saying 4 5/8, we would just say 4.625

4 0

3 years ago

Math study <br> show work

lozanna [386]

Step-by-step explanation:

for the 2 lines to be parallel the angles of crossing the third line must be equal.

and it is a given for 2 crossing lines, that the right top angle is equal to the left bottom angle, and the left top angle is equal to the right bottom angle.

therefore, the 2 indicated angles must be equal :

3x + 48 = 6x

48 = 3x

x = 16

4 0

2 years ago

4 Suppose you throw a dart at a circular target of radius 10 inches. Assuming that you hit the target and that the coordinates o

Lady bird [3.3K]

Answer:

0.04,0.25.0.52

Step-by-step explanation:

Given that you throw a dart at a circular target of radius 10 inches.

Assuming that you hit the target and that the coordinates of the outcomes are chosen at random,

probability that the dart falls

(a) within 2 inches of the center

Here favourable region has area of a circle with radius 2 inches and sample space has area of 10 inches

Prob = $\frac{\pi *2^2}{\pi *10^2} \\\\=\frac{1}{25}$

(b) within 2 inches of the rim.

For within two inches from the rim we have to select area of the ring i.e. area of big circle with 10 inches - area of smaller circle with 10-2 inches

Prob= $\frac{\pi * *8^2}{\pi*10^2} \\=0.64$

c) within I quadrant

area of I quadrant / area of circle=0.25

d) within I quadrant and within 2 inches of the rim

= I quadrant area + 2 inches ring area - common area

= $\frac{\pi*10^2/4 + pi*(10^2-8^2) - \pi(10^2-8^2)/4}{\pi*10^2} \\=\frac{25+36-9}{100} \\=0.52$

3 0

3 years ago