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Nitella [24]
3 years ago
11

PLEASE SOLVE THIS!! Here's the question!!!

Mathematics
1 answer:
geniusboy [140]3 years ago
8 0
The volume is 1733.33 v = lwh /3
The surface area is 1056.05
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PLEASE HELP ASAP!
vazorg [7]

Answer:

A. \displaystyle \frac{6}{10}

Step-by-step explanation:

\displaystyle \frac{9}{15} = \frac{6}{10}

Greatest Common Divisor [GCD]: 1½

I am joyous to assist you anytime.

4 0
4 years ago
Larina received a 50$ gift card to an online store. She wants to purchase some bracelets that cost 8$ each. There will be an ove
Strike441 [17]
8n+10=50 <-- Original Equation

8n=40 <-- Use the Subtraction Property of Exponents to remove the 10 from the left

n=5 <-- Use Division Property of Exponents to remove the 8 from the n and find the unit of n

The number of bracelets Larina can purchase is five.
5 0
4 years ago
Last week, the price of cherries at the corner deli was $4.99 per pound. This week, cherries at the same deli are on sale at a 1
ANEK [815]

Answer:

Your answer should be 15.905625, if it's not 15 percent off per pound.

Step-by-step explanation:

Multiply 4.99 x 3.75 then multiply that answer (18.7125) by .15

That will leave you with 2.806875, which then you subtract that from 18.7125

That will give you your answer, 15.90...

4 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
3. NASA launched the Voyager spacecraft with a mission to observe Jupiter and Saturn. In 1990,
makkiz [27]

The linear function that calculates the expected distance from the sun of the Voyager-2 spacecraft in x years after 1990 is given by:

y = 3.3x + 30.6.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, we have that the distance increases 33 AU each 10 years, hence the slope is given by:

m = 33/10 = 3.3.

Hence:

y = 3.3x + b.

When x = 28, y = 123, hence we use it to find b as follows:

123 = 3.3(28) + b

b = 30.6.

Hence equation to calculate the expected distance from the sun of the Voyager-2 spacecraft in x years after 1990 is given by:

y = 3.3x + 30.6.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

5 0
2 years ago
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