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Softa [21]
3 years ago
8

Ammonium ion (NH4+) reacts with nitrite ion (NO2–) to yield nitrogen gas and liquid water. The following initial rates of reacti

on have been measured for the given reactant concentrations. Expt. # [NH4+] (M) [NO2–] (M) Initial rate (M/h).
1 0.010 0.020 0.020
2 0.015 0.020 0.030
3 0.030 0.010 0.015.
Which of the following is the rate law (rate equation) for this reaction?
a. rate = k [NH4+]2 [NO2-]
b. rate = k [NH4+ ] [NO2-]
c. rate = k [NH4+] [NO-2]2
d. rate = k [NH4+]-1[N02-]
e. rate = k [NH4+] [NO2-]

Chemistry
1 answer:
blondinia [14]3 years ago
3 0

Answer:

c. rate = k [NH4+] [NO-2]2

Explanation:

See attachment

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A water bottle has a mass of 14.0g. Given a density of 1.38g/cm^3, what is the volume of the plastic used to make the water bott
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Answer:

\boxed{\sf Volume \ of \ plastic \ used = 10.14 \ cm^3}

Given:

Mass = 14.0 g

Density (\rho) = 1.38 g/cm³

To Find:

Volume (V)of the plastic used to make water bottle

Explanation:

Formula:

\boxed{ \bold{Density \ (\rho) = \frac{Mass \ (m)}{Volume \ (V)}}}

Substituting value of m & density in the formula:

\sf \implies 1.38 =  \frac{14.0}{V} \\  \\   \sf \implies V =  \frac{14.0}{1.38} \\  \\   \sf \implies V = 10.14 \ cm^3

\therefore

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uysha [10]

Answer:

d. 12.3 grams of Al2O3

Explanation:

The balanced chemical equation of this chemical reaction is as follows:

4Al + 3O2 --> 2Al2O3

Based on the balanced equation, 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

First, we need to convert the mass of aluminum to moles using the formula;

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Molar mass of Al = 27g/mol

mole = 6.50/27

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Hence, if 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

Then, 0.241mol of Al will produce (0.241 × 2/4) = 0.241/2 = 0.121mol of Al2O3.

Convert this mole value to molar mass using mole = mass/molar mass

Molar mass of Al2O3 = 27(2) + 16(3)

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mass = molar mass × mole

mass = 102 × 0.121

mass of Al2O3 = 12.34grams.

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The electron configuration of an element is 1s^ 2 2s^ 2 2p^ 2 How many valence electrons does the clement have? (1 point )
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