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Hunter-Best [27]
2 years ago
15

A wood pole is 12 metres long and is cut into 5 equal sections. If each cut wastes 10 cm of pole, what length would each section

be? *
Chemistry
1 answer:
Sophie [7]2 years ago
6 0

Each section would be 230 centimeters or 2.30 meters long.

<h3>Sectional division</h3>

The original wood pole is 12 meters long.

12 meters = 12 x 100 = 1200 centimeters

It is to be cut into 5 equal sections: 1200/5 = 240 centimeters

But each cut wastes 10 cm of the pole.

          240 - 10 = 230 centimeters.

Thus, each section would be 230 centimeters or 2.30 meters long.

More on sectional divisions can be found here: brainly.com/question/15381501

#SPJ1

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State Boyle's, Charles's, and Gay-Lussac's laws using sentences, then equations
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Explanation:

1. Boyle's Law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}      (At constant temperature and number of moles)

P_1\times {V_1}=P_2\times V_2

2. Charles' Law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T    (At constant pressure and number of moles

\frac{V_1}{T_1}=\frac{V_2}{T_2}

3. Gay Lussac's Law states that tempertaure is directly proportional to the pressure of the gas at constant volume and number of moles of gas

P\propto T    (At constant volume and number of moles)

\frac{V_1}{n_1}=\frac{V_2}{n_2}

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I think is true i took the test but im not sure what i put! Correct me if wrong
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What are half-reactions?
andreev551 [17]

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7 0
3 years ago
Osmium metal, the densest element, has a density of 22.6 g/mL, while hydrogen, the least dense element, has a density of 8.99 e-
KengaRu [80]

Answer:

1. Volume of osmium = 0.044 mL

2. Volume of Hydrogen = 11123.47 mL

3. Osmium is 251390 times denser than hydrogen

Explanation:

From the question given above, the following data were obtained:

Density of osmium = 22.6 g/mL

Density of Hydrogen = 8.99×10¯⁵ g/mL

Mass of osmium = 1 g

Mass of Hydrogen = 1 g

1. Determination of the Volume of osmium.

Density of osmium = 22.6 g/mL

Mass of osmium = 1 g

Volume of osmium =?

Density = mass /volume

22.6 = 1 / volume

Cross multiply

22.6 × volume = 1

Divide both side by 22.6

Volume = 1 / 22.6

Volume of osmium = 0.044 mL

2. Determination of the Volume of Hydrogen.

Density of osmium = 8.99×10¯⁵ g/mL

Mass of osmium = 1 g

Volume of osmium =?

Density = mass /volume

8.99×10¯⁵ = 1 / volume

Cross multiply

8.99×10¯⁵ × volume = 1

Divide both side by 8.99×10¯⁵

Volume = 1 / 8.99×10¯⁵

Volume of Hydrogen = 11123.47 mL

3. Determination of the number of times osmium is denser than hydrogen.

Density of osmium (Dₒ) = 22.6 g/mL

Density of Hydrogen (Dₕ) = 8.99×10¯⁵ g/mL

Dₒ / Dₕ = 22.6 / 8.99×10¯⁵

Dₒ / Dₕ = 251390

Cross multiply

Dₒ = 251390 × Dₕ

Thus, osmium is 251390 times denser than hydrogen.

5 0
3 years ago
Please help me i would greatly appreciate it.. 50 points and will mark brainliest
Nikitich [7]

Answer:

368.92g

Explanation:

Firstly, let's balance the equation which is

2NO + O₂ ---> 2NO₂

Starting with 8.02 mol of NO let's calculate the moles of oxygen which is in a 2 : 1 molar ratio

2NO + O₂

2 : 1

8.02 mol : x mol

Moles of O₂ = 8.02 ÷ 2 = 4.01 mol

Doing the same thing for 18.75 mol of O₂ to calculate the number of moles of NO

2NO + O₂

2 : 1

x mol : 18.75 mol

Moles of NO = 18.75 × 2 = 37.5 however we are told we have 8.02 moles of NO, so we are unable to use 18.75 mol of O₂

Using 8.02 mol of NO to figure out the number of moles of NO₂ :

2NO : 2NO₂

They have the same molar ratio of 2 : 2, so the number of moles is 8.02

Using formula moles = mass / Molar mass

Rearranging to find mass = moles × molar mass

Molar mass of NO₂ = 14 + 16 + 16 = 46

Mass = 46 × 8.02 = 368.92g

5 0
2 years ago
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