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Hunter-Best [27]
1 year ago
15

A wood pole is 12 metres long and is cut into 5 equal sections. If each cut wastes 10 cm of pole, what length would each section

be? *
Chemistry
1 answer:
Sophie [7]1 year ago
6 0

Each section would be 230 centimeters or 2.30 meters long.

<h3>Sectional division</h3>

The original wood pole is 12 meters long.

12 meters = 12 x 100 = 1200 centimeters

It is to be cut into 5 equal sections: 1200/5 = 240 centimeters

But each cut wastes 10 cm of the pole.

          240 - 10 = 230 centimeters.

Thus, each section would be 230 centimeters or 2.30 meters long.

More on sectional divisions can be found here: brainly.com/question/15381501

#SPJ1

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For the reactions below, describe the reactor system and conditions you suggest to maximize the selectivity to make the desired
alexandr1967 [171]

Answer:

hello your question lacks the required reaction pairs below are the missing pairs

Reaction system 1 :

A + B ⇒ D  -r_{1A}  = 10exp[-8000K/T]C_{A}C_{B}

A + B ⇒ U -r_{2a} = 100exp(-1000K/T)C_{A} ^\frac{1}{2}C_{B} ^\frac{3}{2}

Reaction system 2

A + B ⇒ D  -r_{1A} = 10exp( -1000K/T)C_{A}C_{B}

B + D ⇒ U  -r_{2B} = 10^9exp(-10000 K/T) C_{B}C_{D}

Answer : reaction 1 : description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1

condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2

reaction 2 :

description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1

condition to maximize selectivity:

to increase selectivity the concentration of D should be minimal

Explanation:

Reaction system 1 :

A + B ⇒ D  -r_{1A}  = 10exp[-8000K/T]C_{A}C_{B}

A + B ⇒ U -r_{2a} = 100exp(-1000K/T)C_{A} ^\frac{1}{2}C_{B} ^\frac{3}{2}

the selectivity of D is represented  using the relationship below

S_{DU} = \frac{-r1A}{-r2A}

hence SDu = 1/10 * \frac{exp(-800K/T)}{exp(-1000K/T)} * C_{A} ^{0.5} C_{B} ^{-0.5}

description of the reactor system : The desired reaction which is the first reaction possess a higher activation energy and higher temperature is required to kickstart reaction 1

condition to maximize selectivity : To maximize selectivity the concentration of reaction 1 should be higher than that of reaction 2

Reaction system 2

A + B ⇒ D  -r_{1A} = 10exp( -1000K/T)C_{A}C_{B}

B + D ⇒ U  -r_{2B} = 10^9exp(-10000 K/T) C_{B}C_{D}

selectivity of D

S_{DU} = \frac{-r1A}{-r2A}

hence Sdu = 1/10^7  *  \frac{exp(-1000K/T)}{exp(-10000K/T)} *\frac{C_{A} }{C_{D} }

description of reactor system : The desired reaction i.e. reaction 1 has a lower activation energy and lower temperatures is required to kickstart reaction 1

condition to maximize selectivity:

to increase selectivity the concentration of D should be minimal

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the complete question in attached figure

Let 
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y------------------- > theoretical yield 
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