Explanation:
Given :
Amount of solute - sucrose (C12H22O11) = 41 g
Amount of solvent -soda = 355-mL
Molarity of the solution with respect to sucrose= ?
Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.
Formula to find the molarity of solution :
Molarity =
Amount of solvent is given in mL, let’s convert to L :
1 L = 1000 mL
Therefore, 355 mL in L will be :
= 0.355 L
We have the amount of solute in g, let’s calculate the number of moles first :
Number of moles (n) =
Molar mass of C12H22O11 = 342.29 g/mol.
Therefore, n =
= 0.119 moles.
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Answer:
THE MOLARITY OF SODIUM CHLORIDE IN THE CONTAINER IS 0.3846 M.
Explanation:
Molarity of a solution is the number of moles of solute per dm3 of solution.
Mass concentration = Molar concentration * Molar mass
1. calculate the mass concentration;
Mass conc. = 45 g in 2 L
= 45 g in 2 dm3
In 1 dm3, the mass will be 45 / 2
= 22.5 g/dm3 of NaCl.
2. Calculate the molar mass;
(Na = 23, Cl = 35.5)
Molar mass = ( 23 + 35.5 ) g/mol
Molar mass = 58.5 g/mol
3. calculate the molarity
Molarity = mss concentration / molar mass
Molarity = 22.5 g/dm3 / 58.5 g/mol
Molarity = 0.3846 mol/dm3 of NaCl.
The molarity of sodium chloride in the container is 0.3846 mol/dm3
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