Answer: 7.723s
Explanation:
given data:
initial velocity = 7.56 m/s.
friction = 0.0695.
change in velocity = 2.32 m/s
<u><em>Solution:</em></u>
Answer:
The angular momentum of the solid sphere is 0.667 kgm²/s
Explanation:
Given;
radius of the solid sphere, r = 0.15 m
mass of the sphere, m = 13 kg
angular speed of the sphere, ω = 5.70 rad/s
The angular momentum of the solid sphere is given;
L = Iω
Where;
I is the moment of inertia of the solid sphere
ω is the angular speed of the solid sphere
The moment of inertia of solid sphere is given by;
I = ²/₅mr²
I = ²/₅ x (13 x 0.15²)
I = 0.117 kg.m²
The angular momentum of the solid sphere is calculated as;
L = Iω
L = 0.117 x 5.7
L = 0.667 kgm²/s
Therefore, the angular momentum of the solid sphere is 0.667 kgm²/s
Answer: 0.5m/s²
Explanation:
Given that,
acceleration of bike (a) = ?
Mass of bike (m) = 20kg bike
(Note that the displacement of the bike is in the northerly direction)
constant unbalanced force (f) = 10 N
According to Newton's second law of motion, the acceleration of the bike will be directly proportional to force acting on it but inversely proportional to the mass of the bike.
Hence, Force α mass x acceleration
f = ma
Make a the subject formula
a = f / m
Now find the acceleration of the bike
a = 10N / 20kg
a = 0.5m/s²
Thus, the acceleration of the bike pedaled in the northerly direction is 0.5m/s²
Apply Gay-Lussac's law:
P/T = const.
P = pressure, T = temperature, the quotient of P/T must stay constant.
Initial P and T values:
P = 180kPa, T = -8.0°C = 265.15K
Final P and T values:
P = 245kPa, T = ?
Set the initial and final P/T values equal to each other and solve for the final T:
180/265.15 = 245/T
T = 361K