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Alexxandr [17]
3 years ago
5

Can anyone solve this numerical Answer is 2ohms

Physics
1 answer:
Annette [7]3 years ago
8 0

Answer:

4 Ohms

Explanation:

The challenging part in this circuit is the bridged setup (diamond-shaped arrangement made of the 4 Ohm resistors). In general, this would first need to be transformed using the Wye-Delta transform to be solved, but in this case we can make a valid simplification: since the diamond arrangement is completely symmetrical, the voltage at the top and the bottom tip of the "diamond" will be identical and no current flows through the 4 Ohm bridge, hence, this resistor can be removed without changing the resulting resistance. After this, it is easy to see that the equivalent resistance of the modified "diamond" is just 4 Ohms.

The remaining top parallel branch of the circuit will be 8 Ohms, and the bottom parallel branch is nominally 8 Ohms. The resulting resistance therefore is 4 Ohms.

(The answer is not 2 Ohms!)

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A brand new corvette can go from 0 to 85 miles per hour in 4.8 seconds.
klasskru [66]

Answer:

(A) 7.9 m/s^{2}  

(B) 19 m/s

(C) 91 m

Explanation:

initial velocity (U) = 0 mph = 0 m/s

final velocity (V) = 85 mph = 85 x 0.447 = 38 m/s

initial time (ti) = 0 s

final time (t) = 4.8 s

(A) acceleration = \frac{V-U}{t}

         = \frac{38-0}{4.8} = 7.9 m/s^{2}  

(B) average velocity = \frac{V+U}{2}

     =\frac{38+0}{2} = 19 m/s

(C) distance travelled (S) = ut + 0.5at^{2}

  =  (0 x 4.8) + 0.5 x 7.9 x 4.8^{2} = 91 m

5 0
3 years ago
The table provided shows data collected during an experiment:
inn [45]

Answer: (A) Gravitational force are proportional to the masses of the two objects.

Explanation:

6 0
3 years ago
Read 2 more answers
A ball is launched horizontally at 150 m/s from a cliff. What is its vertical speed after 3 seconds?
Setler79 [48]

Answer:

v_f = 30 m/s

Explanation:

v_f = v_I + a*t

v_f = 0m/s + (9.81m/s²)*(3s)

v_f = 29.43m/s

v_f = 30 m/s

Since the object is being launched horizontally off the cliff the only vertical force acting on the ball is gravity which is an acceleration of 9.81m/s². So we have all the flowing information to use the the kinematic equation: v_f = v_I + a*t.

3 0
3 years ago
What waves need molecules in order to transfer energy
nevsk [136]

Answer:

Mechanical waves

Explanation:

Waves are periodic oscillations, that carry energy, but not matter.

Waves are classified into two types:

- Mechanical waves: these waves are produced by the oscillations of the particles in a medium, which can oscillate along the  direction of propagation of the wave (longitudinal wave) or perpendicular to the direction of motion of the wave (transverse wave). These waves can only propagate in a medium, so they cannot travel in a vacuum. Examples of mechanical waves are sound waves.

- Electromagnetic waves: these waves are produced by the oscillations of electric and magnetic field. They are transverse waves. They are the only type of wave able to propagate through a vacuum (so, through space).

Therefore, the waves that need molecules in order to transfer energy are mechanical waves.

4 0
3 years ago
First consider a Carnot engine that operates between a hot reservoir at 58°C and a cold reservoir at -17°C. In running 24 minute
jok3333 [9.3K]

Answer:

Explanation:

Given that,

Hot reservoir temperature is

TH = 58°C

TH = 58 + 273 = 331 K

Cold reservoir temperature

TC = -17°C

TC = -17°C + 273 = 256K

In 24minutes 590 J of heat was removed from hot reservoir

t = 24mins

t = 24 × 60 = 1440 seconds

Then,

Power is given as

P = E / t

P = 590 / 1440

P = 0.41 W

Since this removed from the hot reservoir, then, QH = 0.41W

We want to find heat expelled to the cold reservoir QX

Efficiency is given as

η = 1 - TH/TC = 1 - QH/QC

1 - TH/TC = 1 - QH/QC

TH/TC = QH/QC

Make QC subject of formula

QC = QH × TC / TH

QC = 0.41 × 256 / 331

QC = 0.317 W

7 0
3 years ago
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