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Alexxandr [17]
3 years ago
5

Can anyone solve this numerical Answer is 2ohms

Physics
1 answer:
Annette [7]3 years ago
8 0

Answer:

4 Ohms

Explanation:

The challenging part in this circuit is the bridged setup (diamond-shaped arrangement made of the 4 Ohm resistors). In general, this would first need to be transformed using the Wye-Delta transform to be solved, but in this case we can make a valid simplification: since the diamond arrangement is completely symmetrical, the voltage at the top and the bottom tip of the "diamond" will be identical and no current flows through the 4 Ohm bridge, hence, this resistor can be removed without changing the resulting resistance. After this, it is easy to see that the equivalent resistance of the modified "diamond" is just 4 Ohms.

The remaining top parallel branch of the circuit will be 8 Ohms, and the bottom parallel branch is nominally 8 Ohms. The resulting resistance therefore is 4 Ohms.

(The answer is not 2 Ohms!)

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What is the kinetic energy of a 50-kg child running to catch the school bus at
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Option C

100 J

Explanation:

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The amount of kinetic energy an object has depends upon which of the following factors? I. the object's velocity II. the object'
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8 0
3 years ago
it takes 90 j of work to stretch a spring 0.2 m from its equilibrium position. How muc work is needed to stretch it an additiona
Vinvika [58]

Work needed: 720 J

Explanation:

The work needed to stretch a spring is equal to the elastic potential energy stored in the spring when it is stretched, which is given by

E=\frac{1}{2}kx^2

where

k is the spring constant

x is the stretching of the spring from the equilibrium position

In this problem, we have

E = 90 J (work done to stretch the spring)

x = 0.2 m (stretching)

Therefore, the spring constant is

k=\frac{2E}{x^2}=\frac{2(90)}{(0.2)^2}=4500 N/m

Now we can find what is the work done to stretch the spring by an additional 0.4 m, that means to a total displacement of

x = 0.2 + 0.4 = 0.6 m

Substituting,

E'=\frac{1}{2}kx^2=\frac{1}{2}(4500)(0.6)^2=810 J

Therefore, the additional work needed is

\Delta E=E'-E=810-90=720 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

7 0
3 years ago
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