Answer:
The motion of a projectile is a two-dimensional motion. ... This is called the principle of physical independence of motions. The velocity of the projectile can be resolved into two mutually perpendicular components: the horizontal component and the vertical component. Acceleration changes velocity.
Explanation:
Answer:
a. E=1440KJ
b. E=360KJ
c. E=1.8 J
Explanation:
I have the power (Watts) is expressed as Energy (Joules) / Time (seconds), also I have to
so, for the lightbulb
Analogously, for the microwave
Now, I have to express the efficiency as Heat energy / power * 100 so
Done
<h3><u>Answer;</u></h3>
travel through solids
P waves and S waves are alike in that they<u> both travel through solids</u>.
<h3><u>Explanation;</u></h3>
- <em><u>P-waves and S-waves are types of seismic waves.</u></em> These waves are produced during an earthquake, that transmit energy released around the earth.
- <u><em>P-waves travel the fastest and also travel through solids, liquids and gases. </em></u>They are push and pull waves and thus they cause rock particles to move back and forth.
- <u><em>S-wave son the other hand arrive at a given point after the p-waves. They do not travel as fast as P-waves. They travel through solids but not in liquids and gases.</em></u> S -waves cause the rocks to move side to side.
22. a - (vf^2 - vi^2)/(2d)
a = (0 - 23^2)/(170)
a = -3.1 m/s^2
23. Find the time (t) to reach 33 m/s at 3 m/s^2
33-0/t = 3
33 = 3t
t = 11 sec to reach 33 m/s^2
Find the av velocuty: 33+0/2 = 16.5 m/s
Dist = 16.5 * 11 = 181.5 meters to each 33m/s speed. Runway has to be at least this long.
24. The sprinter starts from rest. The average acceleration is found from:
(Vf)^2 = (Vi)^2 = 2as ---> a = (Vf)^2 - (Vi)^2/2s = (11.5m/s)^2-0/2(15.0m) = 4.408m/s^2 estimated: 4.41m/s^2
The elapsed time is found by solving
Vf = Vi + at ----> t = vf-vi/a = 11.5m/s-0/4.408m/s^2 = 2.61s
25. Acceleration of car = v-u/t = 0ms^-1-21.0ms^-1/6.00s = -3.50ms^-2
S = v^2 - u^2/2a = (0ms^-1)^2-(21.0ms^-1)^2/2*-3.50ms^-2 = 63.0m
26. Assuming a constant deceleration of 7.00 m/s^2
final velocity, v = 0m/s
acceleration, a = -7.00m/s^2
displacement, s - 92m
Using v^2 = u^2 - 2as
0^2 - u^2 + 2 (-7.00) (92)
initial velocity, u = sqrt (1288) = 35.9 m/s
This is the speed pf the car just bore braking.
I hope this helps!!
