Answer:
16
Step-by-step explanation:
The figure shown is a trapezoid
Area of a trapezoid = 1/2(bottom base length + top base length) × height
Bottom base length = 7 units
Top base length = 1 unit
Height = 4 units
So area = 1/2 ( 7 + 1 ) × 4
==> add 7 and 1
Area = 1/2 (8) × 4
==> multiply 1/2 and 8
Area = 4 × 4
==> multiply 4 and 4
Area = 16
You give us no choices. The one that represents the most common factors is
3a(16 a^2- 25) is one choice another could be
3a(4a - 5)(4a + 5)
Answer:
4.5 + 5.5 + 6 = 16
Step-by-step explanation:
Answer:
f(-1) = 81
Step-by-step explanation:
Given the function,
, we can find f(-1) by plugging in -1 into the function:
![f(x) = (x - 8)^{2}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28x%20-%208%29%5E%7B2%7D)
![f(-1) = (-1 - 8)^{2}](https://tex.z-dn.net/?f=f%28-1%29%20%3D%20%28-1%20-%208%29%5E%7B2%7D)
![f(-1) = (-9)^{2}](https://tex.z-dn.net/?f=f%28-1%29%20%3D%20%28-9%29%5E%7B2%7D)
<em>f </em>(-1) = 81
<span>The problem says that Donovan is using similar rectangles, so you can calculate the length of the second rectangle, by using the similarity concept.
We have that the first rectangle </span>is 2 inches wide and 6 inches long, and the second rectangle must has<span> 5 inches wide. Then:
2/5=6/L (L: </span>the length of the second rectangle).
<span> 2L=6x5
2L=30
L=30/2
L=15 inches
H</span><span>ow long must the second rectangle be?
</span><span>
The answer is: The second rectangle must be 15 inches long.
</span>