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2 years ago

1 question~Which inequality is true? Use the number line to help.

Mathematics

1 answer:

Trava [24]2 years ago

5 0

അത് പോലും അറിയില്ല

എനിക്കും അറിയില്ല

just for a രസം

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Ryan only work for 9 1/4 hour everyday because he takes 1 1/4 hour of break so you minus the from the total and get the sum of 9 1/4

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3 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

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3 years ago

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3 years ago

What ordered pair is a solution for y-4=7(x-6)

777dan777 [17]

The ordered pair (6 , 4) is a solution for y - 4 = 7(x - 6)

Step-by-step explanation:

The point-slope form of a linear equation is:

$y-y_{1}=m(x-x_{1})$ , where

m is the slope of the line
$(x_{1},y_{1})$ is a point on the line

Any point on the line is a solution for the equation of the line

The solution of an equation is the values of x and y which make the left hand side is equal to the right hand side

∵ The equation is y - 4 = 7(x - 6)

- Compare the equation by the point-slope form above

∴ m = 7

∴ $x_{1}$ = 6 and $y_{1}$ = 4

- That means point (6 , 6) lies on the line

∴ Point (6 , 4) is a point on the line which represents the

given equation

∵ Any point on a line is a solution of the equation of that line

∴ (6 , 4) is a solution of the equation

The ordered pair (6 , 4) is a solution for y - 4 = 7(x - 6)

Learn more:

You can learn more about the linear equations in brainly.com/question/1284310

#LearnwithBrainly

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