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3 years ago

7

What's a real world problem involving a percent greater then 100%

1 answer:

AveGali [126]3 years ago

8 0

Buying something that costs more than $1.00 can be an example.

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Write and solve a real-word word problem in which there are 3 tables for every 8 chairs

Talja [164]

Answer:

tate is hosting a party and he has 23 people coming over. for every table he buys, 8 chairs come with it. how many tables should tate buy so that he can seat all of his guests?

Step-by-step explanation:

6 0

3 years ago

A store has a 25\%25% off sale on coats. With this discount, the price of one coat is \$34.50$34.50. What is the original price

timama [110]

Answer:

$46

Step-by-step explanation:

A percent is a portion of 100. If we receive 25% off then we pay 75% of the price. 100%-25%=75%. $34.50 is 75% of the original price. We find the new price through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities. For example, we will compare percent over percent to an equal ratio of $ to $.

$\frac{75}{100} =\frac{34.50}{y}$

I can now cross-multiply by multiplying numerator and denominator from each ratio.

$75y=100(34.50)\\75y=3450$

I now solve for y by dividing by 75.

$\frac{75y}{75} =\frac{3450}{75} \\y= 46....$

The original price was $46.

5 0

4 years ago

Muffins are sold in packages of 18 and cost $27 per package. Each of the 6 friends gets an equal share of muffins from p package

anzhelika [568]

3 x 6 to the power of 4 divide that by how many people their are !

8 0

3 years ago

I need some help with this one I'm lost!

SpyIntel [72]

Answer:

-334

Step-by-step explanation:

tyes sfdfa d

3 0

3 years ago

第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

8 0

1 year ago