Y intercept means x = 0, on x= 0 y is also zero so the cordinate is (0,0)
X^2 + y^2 = (3x^2 + 2y^2 - x)^2
2x + 2y f'(x) = 2(3x^2 + 2y^2 - x)(6x + 4y f'(x) - 1) = 36x^3 + 24x^2yf'(x) + 24xy^2 + 16y^3f'(x) - 4y^2 - 18x^2 - 8xyf'(x) + x
f'(x)(2y - 24x^2y - 16y^3 + 8xy) = 36x^3 + 24xy^2 - 4y^2 - 18x^2 - x
f'(x) = (36x^3 + 24xy^2 - 4y^2 - 18x^2 - x)/(2y - 24x^2y - 16y^3 + 8xy)
f'(0, 0.5) = -4(0.5)^2/(2(0.5) - 16(0.5)^3) = -1/(1 - 2) = -1/-1 = 1
Let the required equation be y = mx + c; where y = 0.5, m = 1, x = 0
0.5 = 1(0) + c = 0 + c
c = 0.5
Therefore, the tangent line at point (0, 0.5) is
y = x + 0.5
Correct histogram: top-right corner
Step-by-step explanation:
The picture is missing: find it in attachment.
A histogram is a type of plot representing data divided into classes. The classes can be represented using bars with same width: if so, the height of each bar is proportional to the number of data inside each class.
Here by looking at the table in the figure, we notice that:
- There are 3 data in the 800-899 class: 805, 805, 872
- There are 5 data in the 900-999 class: 910, 919, 923, 950, 989
- There are 8 data in the 1000-1099 class: 1004, 1010, 1020, 1051, 1056, 1085, 1094, 1098
- There are 6 data in the 1100-1199 class: 1108, 1128, 1133, 1150, 1150, 1187
- There 3 data in the 1200-1299 class: 1209, 1220, 1298
Therefore, the correct histogram representing the set of data is the histogram on the top-right corner, which has respectively columns of height 3, 5, 8, 6 and 3.
Learn more about histograms:
brainly.com/question/3517446
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1) given
2) definition of an angle bisector
3) reflexive
4) (ASA)
5) (CPCTC)
To solve this question all you have to do is input the X and y coordinates and test each point in the question. To see which of those points. Have the left hand side equal to the right hand side after doing all of the operations.