Answer:
(12.1409, 14.0591
Step-by-step explanation:
Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.
Group Group One Group Two
Mean 87.600 74.500
SD 1.000 1.500
SEM 0.316 0.433
N 10 12
The mean of Group One minus Group Two equals 13.100
standard error of difference = 0.556
90% confidence interval of this difference:
t = 23.5520
df = 20
Step-by-step explanation:
12:56pm to 1:00pm = 4 min
1:00pm to 2:00pm = 1 hour
2:00pm to 2:33pm = 33 min
Total time = 4 min + 1 hour + 33 min = 1 hour 37 minutes.
Answer:
s = -3
Step-by-step explanation:
8s + 9 = 7s + 6
Subtract 7s from each side
8s-7s + 9 = 7s-7s + 6
s+9 = 6
Subtract 9 from each side
s + 9-9 = 6-9
s = -3
Answer:
b(4x+3)(2x+1)
Step-by-step explanation:
just took the test
The perimeter of the enlarged garden is 16.56 meters.
<u>Step-by-step explanation:</u>
The garden is in the shape of a rectangle.
- The length of the rectangle = 5.4 meters.
- The width of the rectangle = 1.5 meters.
The Rectangle is enlarged by increasing the length and width by 20%.
<u>To find the enlarged length :</u>
The original length 5.4 is increased by 20%.
⇒ (20/100) × 5.4
⇒ 0.2 × 5.4
⇒ 1.08
- The 20% of the length is 1.08
- The enlarged length is 5.4 + 1.08 = 6.48 meters.
<u>To find the enlarged width :</u>
The original width 1.5 is increased by 20%.
⇒ (20/100) × 1.5
⇒ 0.2 × 1.5
⇒ 0.3
- The 20% of the width is 0.3
- The enlarged width is 1.5 + 0.3 = 1.8 meters.
The perimeter of the enlarged rectangle is found by substituting the enlarged values of length and width in the perimeter formula.
Perimeter of the enlarged rectangle = 2 (length + width)
⇒ 2 (6.48 + 1.8)
⇒ 2 × 8.28
⇒ 16.56 meters.
∴ The perimeter of the enlarged garden is 16.56 meters.
